<p>oh i got it sorry! that was really easy...</p>
<p>A monkey sits atop a tree and sees two birds. He can look at one of the birds by tilting his head up at an angle of q1 above the horizontal. He can look at the second bird by tilting his head down at an angle of q2 below the horizontal. If both birds are a horizontal distance of d meters from the tree (i.e., one is flying directly above the other), how far apart vertically are the two birds, in meters?</p>
<p>Hmm…is it just me or does this seem really simple?</p>
<p>.4<em>5000-.6</em>2000=800.</p>
<p>(dtan(q1) + dtan(q2)) meters for the second one.</p>
<p>agree w/ The Notorious B.I.G. on the second one… u sure that aint an ACT problem???</p>
<p>how did you get the 2nd one? and thanks biggie smalls :)</p>
<p>Draw it out. This might look really confusing, but picture lines going from the monkey to the birds, and the v’s are the vertical distances. </p>
<p>Well, here goes nothing…</p>
<p>…Bird one
…q1…v1
Monkey…d…
…q2…v2
…Bird Two</p>
<p>Now, the tangent of q1 is opposite side, v1, over the adjacent side, d. Now, to get v1, simply multiply both sides of the equation by d</p>
<p>tan(q1)=v1/d
dtan(q1)=v1</p>
<p>You can do the same thing for v2, and then you simply add v1 and v2 to get the vertical distance between the two birds. Hope this helps.</p>
<p>Props to the ingenuity above !!! ^ lol</p>
<p>P.S. I have recently seen this problem. Isnt it from PR 11 Tests ?</p>
<p>lol i remember it from a sparknotes math 2 c practice test.</p>
<p>Your truth !!! ^ Thats where I saw it. ;)</p>