<p>It was 2-20 with 2 being least, 20 being most, 6 being median, and 3 being mode. I got 1,2, and 3.</p>
<p>For the symbols one I think i got 1 only</p>
<p>It was 2-20 with 2 being least, 20 being most, 6 being median, and 3 being mode. I got 1,2, and 3.</p>
<p>For the symbols one I think i got 1 only</p>
<p>wait was the 2-20 one a multiple choice for you?</p>
<p>I got I+II for the symbols, and I+II+III for the 2-20</p>
<p>Yeah it was. The I was 7 the II was 10 and the III 8.5 I think. Or some combination of those 3.</p>
<p>by the symbols question i mean the x(weirddot)y=xy+x+y thingy...</p>
<p>Sorry, I was thinking of the wrong problem for the 2-20</p>
<p>darkruler2 my answers for those r same as urs.. hope were both right...
can any of u gus temme how to do the polygon and the lenght of semicircles questions.. thanks..</p>
<p>Yeah sky i understood what you meant and I think I just realized another bad mistake on it.</p>
<p>OH!!!!!!
The motel/hotel.</p>
<p>Was it Night #3?</p>
<p>Was the numbers 1-10 with 6 or 7 as the median, and 3 occuring the most? Wasn't that ALL of them because they asked for REAL NUMBERS (anything can be a real number except with i's)..or did I just combine two questions?</p>
<p>wt bout the transformations question..
i think the line was about 2 units down so it wub like g(X)=f(X)-2 or right.. or was it 2 units up and g(X)=f(X)+2??</p>
<p>I got #3 for that one Edieee</p>
<p>And you did combine two but it was all real numbers so it was all</p>
<p>Eddieee u comibined 2 questions.. the motel/hotel is anohter one while the numbers one is another one...</p>
<p>For the transformatio i thoght it was g(x)=f(x) + 1 because if i was thinking straight, there was only 1 point seperating the two on the y-axis. But then again, i obviously made alot of mistakes today.</p>
<p>yup even i got 3 for the hotel/motel...</p>
<p>ya neb ur right.. i said 2 by mistake.. tho im not so sure if it was f(X)+1 or f(X)-1...</p>
<p>anybody got ne idea bout the polygon question n the length of semicircles....</p>
<p>Surely Sky. For the polygon one, you know x+y=80. Also, you know all angles are the same. So X+Y+2angle=360.</p>
<p>Thusly,
2A+280,
A=140
if you know the abgle, you can use..</p>
<p>(N-2)(180)/N=A, where N is the nube of sides. So you get N=9, thus 9 sides. I had best get an 800 on mth, I sweating bullets on that one and 3 others. It probably damaged my health. ;)</p>
<p>the length of the semicircles was 12pi ; you just calculate the diameter of each circle and divide by 2, no matter what size you made each circle (they could have ranged greatly given what they gave you) you would have gotten 12pi if you found it out in that manner</p>
<p>darkruler.. So X+Y+2angle=360.
whats 2angle.???</p>
<p>umm.. i apologise for sounding dumb but how do we calculate the diameter?</p>