SAT Geometry problem

<p>Anyone know what the answer was to the last grid in problem?</p>

<p>It was a square with a triangle inside it, and u were given the area of the triangle and that one side was 2/5 of another.</p>

<p>70/3 was the answer.</p>

<p>70/3 or 23.3</p>

<p>70/3..for sure... everyone i know got that...
q ______<strong><em>r
|............/.|
|........../...|
|</em></strong><strong>/</strong>
|
p t s</p>

<p>pt=2/5 of ps and triangle rst has an area of 7</p>

<p>so draw..
__________
|............/.|
|........../.7|
|__<strong><em>/</em></strong>|
(2/5)x (3/5)x </p>

<p>so area of triangle=</p>

<p>1/2 * (3/5)x * y =7</p>

<p>(3/10)x * y = 7</p>

<p>y=(70/3)x</p>

<p>therefore:</p>

<pre><code> __________
|............/.|
|........./..7| (70/3)x
|__/|
(2/5)x (3/5)x
</code></pre>

<p>(70/3x)*x=(70x/3x)=70/3</p>

<p>...either that helped or confused the living hell out of you</p>

<p>PS. [...]'s are used as fillers so the rectangle maintains its shape in the post (since CC delete erroneous spaces)</p>

<p>alrite thanx guys I didnt get 70/3, but i worked it out somewat logically and got 23
too bad no partial credit:(</p>

<p>Q ___<strong><em>R
|............./.|
|............/7|
P</em></strong>
_T/...S</p>

<p>PT: 2/5 PS
TS: 3/5 PS
Area of Triangle RTS: 7</p>

<p>(1/2)<em>(3/5PS)</em>(RS) = 7 <strong>(1/2<em>Base</em>Height=7)
(3/5PS)*RS = 14 </strong>_<strong><em>(Bring the 1/2 Over)
PS * RS = [70/3] _</em></strong>
_ (Length * Width=70/3)</p>

<p>Final Answer End of Story</p>