<p>oh yah sorry I meant first quadrant!!</p>
<p>they intersect in the 1st quadrant. for the root question, wasn’t it 7 not 6? oh crap if it was 6 and not 7 that means i maybe missed 3 with 5 omit…-8 still wont be 800 right?</p>
<p>Yeah it was first quadrant. Phew. almost had a heart attack…
wait…</p>
<p>4,5,8,8,12, x</p>
<p>if you do 11 as x, it comes out to 8 for median and mean.
if you do 6.5 as x, it comes out to 7.25…</p>
<p>Am I wrong on this one?</p>
<p>1.25 + .75[x]?
Any part thereof meant that decimals = whole?</p>
<p>Isn’t [x] = Int(X)
So [2.8] = Int(2.8) = 2 =/ any part thereof</p>
<p>Any part thereof means remainder = whole, so isn’t it </p>
<p>1.25 + .75[x+1]?</p>
<p>Root question: I got 6 because both functions included 7 so you only count 7 as one zero not two</p>
<p>Sent from my SCH-I500 using CC</p>
<p>No, that’s where it was different. [x] was NOT int. it said [x] meant the integer GREATER than or equal to x, not less than or equal to x (which would be int())</p>
<p>what do u guys think the curve is gonna be??</p>
<p>or what do u think the cut off for an 800 is gonna be ?</p>
<p>The people that picked [x + 1] over thought the problem… it’s 1.25 + .75[x]</p>
<p>Sent from my SCH-I500 using CC</p>
<p>it is 1.25 + .75(x) i think. the brackets mean round to the least integer greater than x.</p>
<p>Yes hopefullygood, that’s exactly why it was correct.
any part of a mile was charged the same - .75</p>
<p>Hopefully -7 = 800, if not definitely -6=800</p>
<p>Sent from my SCH-I500 using CC</p>
<p>yup i got 6.5 for the median mean one</p>
<p>Well, there goes my -1. Now it’s -2.
Hopefullygood777, seems like we’re on the same boat.</p>
<p>the one with the how many triangles could be formed was none right?</p>
<p>Who remembers getting 6pir^2?</p>
<p>Sent from my SCH-I500 using CC</p>
<p>I got that Joshi.</p>
<p>^I do! but i dont remember the question</p>
<p>@King Yea, it was none.
Well, at least that’s what I got.</p>
<p>Surface area of the cylinder?
I got 6PiR^2 as well.</p>
<p>@king i got that it was none too.
@joshi,king the question was</p>
<p>surface area of a cylinder = ?
r = r
h = 2r</p>