<p>we basically need more people to join this thread to get more definite answers, i am convinced the quad one had 2 values that equal 0, unless others were like -100 and 100, or something to that extent.</p>
<p>what was the actual question with the question whose answer was (3,4)?</p>
<p>something along the lines of , "What are the coordinates of the intersection between the vertical and its perpendicular line" or something.</p>
<p>quad Q:
exponent quad -- two values equal zero X^0 = 1 (theres two values)
set base = 1, subtract one, thus set equal to zero 1^n = 1 (theres two more values)</p>
<p>do u remember the question for the perpendicular line, im just trying to think whether i said 2,4 or 3,4</p>
<p>wait, matty 7589, if u have 2 values to make the top quad value 0, then that means that the bottom quad ^0=1. It was asking for when it equals 0, thus that means that the bottom must be 0 because 0^anything=0. You are saying that there are 2 values up top to make it 0, but then that gives u a final answer of 1--not what they were asking for.</p>
<p>Yes! I said 3,4 but wasn't confident.</p>
<p>Maybe I'm retarded, but what about that one that was a circle, and it gave you a diameter and the other line across it, that had a length of 4. All they told you was that the part of the circle's perimeter was 60 degrees... for me, the second to last question. I did end up with an answer, but I don't think it was the right one.</p>
<p>42 degree was .9 slope i believe.</p>
<p>wait, did u get 4 or 2 for the quad one we were talking about? also, that one u r talking about where they only gave u the arc, was that the one when they said one leg was 8?</p>
<p>do you guys remember the letter of the choice for the answer 81? Was it letter B? the question asked for the area of the largest square. the three values for the 3 squares had to be made up of consecutive odd integers.</p>
<p>umm, 81 was correct but i think it might have been C, they could've been in ascending order. i really have no clue tho so dont go on my word.</p>
<p>liver-
you set the base equal to to 1, but then to solve the equation, subtract 1 and set it equal to zero, which ultimately finds the two locations where the base is equal to one</p>
<p>guys, im just afraid i put 2,4 instead of (3,4) for the perpendicular one, why wasnt it (2,4)? anyone have an answer to the one with the quadratic function to the power of another quadratic function?</p>
<p>matty, so then is the answer to that quadratic one 2 or 4? i dont think u can just subtract one. basically, in order to get something like (x^2+4x+3)^(x^2+7x+10)=0, u need to see when the bottom quadratic=0, not the top because anything ^0=1</p>
<p>ok -- </p>
<p>you solve the exponent for zero. using quad eq. there is two answers, or two values where the whole equation is equal to one.</p>
<p>then you set the base equal to one, because in order for the eq. to equal one, you need either the exponent to equal zero or the base to equal one.
x^2 + 4x + 3 = 1, or X^2 + 4x + 2 = 0
Solving that quad. eq. will find you the zeros of the SECOND equation, but the places where the FIRST equation is equal to one</p>
<p>thus there are FOUR answers</p>
<p>liverpudian- the answers for the three consective odd intergers was not in ascending order. It was in descending, but i'm trying to remember if there was another value between 121 and 81. hopefully there weren't, which would make 81 letter choice B. Did the quadratic equation to a power of a quadratic equation ask you for how many values of x made the equation equal to 1? if it did, then it's 2 values.</p>
<p>no worries, it was difficult. thats why it was # 50</p>
<p>Here...i think I've found the most succinct way to voice what I am thinking. Nothing to the power of 0=0, thus, the top quadratic function means nothing. Now, all you find is the bottom quad fct and when that equals 0, which is twice. The answer is 2.</p>
<p>you were solving the equation to be set equal to ONE not zero</p>
<p>Ahh, here is the vital place we differ. I believe it said =0, not =1. scorpio- was the quadratic one equal to 1 or 0?</p>