<p>pretty sure it was 1.</p>
<p>100% sure it was one. sorry liver, but at least you knew what you were doing, not like that'll get you the point or anything, but still!!!!</p>
<p>dude, why are there only 3 people in this thread?</p>
<p>wait then, if it was equal to 1, then surely the bottom quadratic could equal anything if the top quadratic equals 0. the bottom could equal absolutely anything and you would just need the top to be 0 to have it equal 1.</p>
<p>lol (10char)</p>
<p>yes, but the top exp. only equals zero at two x-values, so the base will only have two base values where the exp. = 0</p>
<p>i have no clue, i wish more would join. we definitely need to ask someone else the answer to that quadratic one because i am yet to be convinced.</p>
<p>matty- tell me exactly how you would do it for this (x^2+4x+3)^(x^2+7x+10)=1. ok, now, the x values for the top one are -5, and -2. go on</p>
<p>you guys, we are not even supposed to be discussing answers online. I feel bad.</p>
<p>i thought we could after everyone took the test?</p>
<p>oh really, apparently they r on all other threads. if they dont want us to tho, then ill stop.</p>
<p>"also, that one u r talking about where they only gave u the arc, was that the one when they said one leg was 8?"</p>
<p>Wait me? Haha. I'm walking about the one with the circle that I think was something like this:
<a href="http://img.photobucket.com/albums/v382/_La_Pistolera/lala.jpg%5B/url%5D">http://img.photobucket.com/albums/v382/_La_Pistolera/lala.jpg</a></p>
<p>Anyone remember the answer?</p>
<p>i thought the u just used pythag theorem to find that one, wasnt it root48. matty, im still waiting, haha</p>
<p>idk, but that collegeboard thing said : "sharing essay questions or multiple-choice questions with anyone for any reason is a violation of test fairness policy". But I mean, lots of kids still do it.</p>
<p>i dont think it was root 48, i just know u used pythag theorem because you could find some angles in there to suggest there was a right angle.</p>
<p>well ok -- ill just finish this explanation and thats it... plus this isnt the exact equation so i guess its okay:
(x^2+4x+3)^(x^2+7x+10)=1
you said (x^2+7x+10)=0 when x = -5, and -2, so there are two answers, whatever the base equals at -5 and -2 doesnt matter, because at those values the exponent = 0 , which makes the eq. 1 (two answers)
now, for the equation also to be = 1,
(x^2+4x+3) = 1, or (x^2+4x+2) = 0
solve the second equation for the zeros. yes, these values are the zeros of (x^2+4x+2), but the x-values where (x^2+4x+3) = 1; thus, whatever the exponent for these x values the eq. will equal one when the base = 1(two more answers)</p>
<p>there's your four</p>
<p>pump problem: three was the units per time. i think physics helped me with that.</p>
<p>average heights: you needed to know the other kids avg heights</p>
<p>perpendicular line: ...just like (3,4). the first one was just x=3, right? and the second was perpendicular and went through (something,4)..so it had to be (3,4)</p>
<p>slope of the line: 0.9</p>
<p>quadratic: there were four. set the bottom equal to 1, and the top equal to 0..four solutions. (1^x=always 1, x^0=always 1) two solutions each.</p>
<p>if I get anything below a 700, i'm paying to have it hand scored. i mean, unless i was missing a concept or something...</p>
<p>Math was easy. Can someone tell me the curve of this test?</p>
<p>there is no curve. if you get 50 right, you get an 800. 49 right..780. that's the only bad part about math I</p>
<p>That is really very bad.</p>