SAT May 2009 Math

<p>What was the answer to the function f(a)=f(b) with a and b being positive integers or whatever? Explain how u got ur answer plz</p>

<h2>What was the answer to the function f(a)=f(b) with a and b being positive integers or whatever? Explain how u got ur answer plz </h2>

<p>Line with slope 0.</p>

<p>Think about it, no matter what value you enter for the function, it will yield the same y value.</p>

<p>No new confirmed answers? Please keep this updated, I’m off to watch Bulls vs. Celtics</p>

<p>Quadratic- 12
Vertices- 1/5
Triangles with shaded part – 3pi
b-a = 9
Venn Diagram 1319
Pie Graph 832
27/8
Logic- calc/wed
1<x<2 area=“” of=“” figure=“” with=“” triangles=“” on=“” inside=“” rectangle-=“” 250=“” f(a)=“f(b):” line=“” slope=“” 0=“” pq=“”>PR
Wire- 6
Beads- blue
Tin/copper- 19
Scissors- 1600
Triangle with <of 79,=“” colinear=“” angle=“101” 3x=“6-” 17=“” f(x)=“”> f(3)- 5
y^2 - 2y
mode < mean < median (70 < 75.5 < 80)
Sequence (100,2,100,4,100,6) - 0
Slope = -2/3
2x + by and 2x + 10y parallel b=10
Y = x^y + x (special function with delta sign) - 2
area of two triangles and 3x4/2 + 5 x 12/2 = 36
Earthquake chart- 562
|a-b| =< 6
reflection problem= -(a+b)
Fuel Economy- Car D
Triangle problem with a 140 degree angle, asking for top angle- 90 degrees</of></x<2></p>

<p>I thought the reflection problem was -a + b. Since you’re flipping it about the y axis, the x-coordinate changes sign, not the y-coordinate.</p>

<p>I thought the reflection problem was -a + b. Since you’re flipping it about the y axis, the x-coordinate changes sign, not the y-coordinate. </p>

<p>the problem asks u to reflect it across both lines.</p>

<p>it asks you to reflect it across 2 axis; the y and then the x. I just picked an easy point for the starting one (i think it was point P) and I used (1,1) and then just started reflecting. can’t remember what the answer was but i know i got it right :)</p>

<p>it reflected about the y axis and the x axis as well^</p>

<p>wait why was vertices 1/5?</p>

<p>wasnt there one figure that had more than 5 vertices and there was 6 total figures</p>

<p>mode < mean < median (70 < 75.5 < 80)</p>

<p>this was choice D correct???</p>

<p>@ RPizzle, no there were five figures…maybe your nerves got you.</p>

<p>well was 1/6 a choice lol?</p>

<p>b/c i seem to remember that…altho if there was 5 figures i’m sure i MUST have out 1/5</p>

<p>^ yea i do not think that 1/6 was a choice…it was (1 through 4)/5.</p>

<p>I was just thinking about all the test centers that were closed for swine flue and the kids who are on here getting all the answers for the test :-p. Lucky them! hahah too bad my test wasn’t postponed :-(. Anyways, I left 3 blank and missed 2 or 3…would I top 700 by any chance?? Thanks! Best of luck to ya’ll.</p>

<p>^ Those whose test centers were closed will take a different version of the test. </p>

<p>3 omit and 2 wrong would be 710; 3 omit and 3 wrong would be 690.</p>

<p>You get a different test if your original test centre closed.</p>

<p>What did everyone get for the I, II, III question?
One of the answer choices was “has three factors”, and another was “a/c” and another “a=bc”.
I put C/ (I and II).</p>

<p>@cebollas: I got C too. But what about this case, a=bd, b=cd=> a=cd^2=> there are only two factors.:(</p>

<p>^^ i see what ur saying for the factor question, but in your example wouldnt b count as a factor too</p>

<p>No, it would have itself, 1, and the other number.</p>

<p>does anyone remember what section the question about what day and what test(calc on wednesday) was in? was it the one with the grid ins?
and did anyone else have sections 2 and 3 math?
can section 2 be experimental?
and does anyone remember any other questions that were in the experimental math section with the logic question about a test?</p>