<p>Yeah, you use the points they give you to solve for the proportionality constant, let’s call it k.</p>
<p>(y-1) = k(x+1)</p>
<p>Once you have k, go solve for a and b and subtract. Pretty simple.</p>
<p>19 tin? .</p>
<p>19 is correct</p>
<p>19 is what I got !</p>
<p>confirmed answers</p>
<p>Quadratic- 12
Vertices- 1/5
Triangles with shaded part – 3pi
b-a = 9
1319- don’t know which question
Logic- calc/wed
1<x<2 area=“” of=“” figure=“” with=“” triangles=“” on=“” inside=“” rectangle-=“” 250=“” f(a)=“f(b):” line=“” slope=“” 0=“” pq=“”>PR
Wire- 6
Beads- blue
Tin/copper- 19
Scissors- 1600</x<2></p>
<p>Scissors was experimental right? I don’t remember such a question.</p>
<p>Can we go over the PQ>PR question? I had that at first but I changed it. If you draw out a diagram, it makes an isosceles triangle, which means that the altitude is the median, which means that QR = RS, so PQ > RS because the hypotenuse has to be greater than the leg, QR. I was conflicted though, because by the same logic PQ has to be greated than PR. Damn, I had PQ > PR first too…</p>
<p>What is the vertices question? 1/5?</p>
<p>what was teh scizzor one?</p>
<p>no scizzors was on the test. </p>
<p>also, the one with the graph was 4, right?</p>
<p>Scissors not, I had it and I had writing experment.</p>
<p>I play wow, you do direct relationship </p>
<p>(y-1)=k(x+1) solve for k and plug in x values for a and b… i got something like 27-16 …</p>
<p>You got 28-19, but yeah.</p>
<p>What exactly was the vertices question? I don’t remember it. Can somebody describe the question?</p>
<p>one where you have to find a place where F(x) > F(3) is 4, right?</p>
<p>vertices- they give you a bunch of shapes and ask you which one has more than 5 vertices. Only hexagon worked, so 1/5</p>
<p>i think it was 5. i dont think 4 was an answer</p>
<p>1319- dont know which question</p>
<p>^ I’m thinking this was the pie chart one with summer jobs</p>
<p>what was the f (a)=f (b)…i think i put the parabola, if the slopes are zero then wouldnt they just be parallel, and therefore not be able to have equal y values?</p>
<p>^ same as the given value of y.</p>
<p>i don’t think 4 was a choice, i think the choice was 5, it was the only positive one so you probably got it right</p>