<p>Which of the following does not react with a dilute solution of sulfuric acid?
a) NaNO3
b) Na2S
c) Na3PO4
d) Na2CO3
e) NaOH</p>
<p>B? I'm guessing that because it has sulfur in it.</p>
<p>its A.
haven't been able to find the reason, yet</p>
<p>Why there isn't a single organic chemistry problem in the newest sat subject test book?</p>
<p>The following hydrogen halides (HF, HCl, HBr, and HI) are all polar molecules. The strength of the acid each forms in water is based on which of the following?</p>
<pre><code> I. The polarity of the molecule
</code></pre>
<p>II. The size of the molecule
III. The strength of the bond</p>
<pre><code>(A) I only
(B) II only
(C) III only
(D) I and III
(E) II and III
</code></pre>
<p>D? I'm guessing here.</p>
<p>well, since "strength" depends on how much it dissociates, i'm leaning towards I and III
so D</p>
<p>btw, i found the reason as to why its NaNO3 that does not react w/ dilute sulfuric acid:
reason is that it requires heat to react w/ sulfuric acid.....found this in the CB book :)</p>
<p>D yes i mean D</p>
<p>The answer is E. II and III</p>
<p>The strength of the acid formed when each of these hydrogen halides is dissolved in water is dependent on the size of the molecule and the strength of the bond in the molecule. For example, the small size of F contributes to the strength of the bond that forms between it and H. F is so strongly attracted to H that the H cannot be easily removed by hydration, so HF remains primarily undissociated in aqueous solutions and is classified as a weak acid.</p>
<p>Although I get why II is true, I dont see why polarity doesn't affect the strength of the acid</p>
<p>Good Luck tomorrow everybody! I'm hitting the hay (Its 10:15 here).</p>
<p>I'm gonna play Madden 2007, and then I'm gonna go sleep. Good luck to everyone here!</p>
<p>Situation: A rubber tube is connected to a flask; there is Hg in the U-shaped tube; the Hg level is balanced before the injected of isopropanol into the flask. With the injection of isopropanol, the level of Hg rises away from the flask. </p>
<p>Which of the following changes in the experiment would cause the pressure to vary?</p>
<p>Doubling the volume of liquid isopropanol injected into the flask.
Increasing the temperature of the system to 30 degrees. </p>
<p>I don't understand why both of these answers aren't true. Please someone help!</p>
<p>Wait, nevermind, I get it now. :)</p>
<p>good luck to all!</p>