<p>yes... my AIM is silvachik08 for now...
IM me</p>
<p>I'm gonna have to stay thank you AP Chem for that.</p>
<p>SO3 + H2O -> H2SO4 (or H+ + HSO4-)
Glass...yeah. silicon dioxide. Ozone...allotrope of oxygen</p>
<p>What about the one that went "NO2(g) = NO + O2+ heat" or something that asked what would happen if the system was placed in ice water. Choices were:</p>
<p>I. increase in pressure
II. increase in volume
III. increase in concentration of NO2 or something.</p>
<p>III only!!</p>
<p>Pressure would decrease when temp. decreases..
so would volume......</p>
<p>But concentration will increase.. Le'Chatlier's principle</p>
<p>Gay Lussac's law =</p>
<p>T1 P1
--- = ----
T2 P2</p>
<p>Charles's law</p>
<p>V=kT</p>
<p>NO2 would increase since when temperature decreases and reaction is exothermic, reaction shifts to the left..</p>
<p>I thought it was I only. What did anyone else put?</p>
<p>I'm not sure about the NO2 problem.</p>
<p>If you're putting it in ice, according to Le Chats, it'll try to compensate for it by shifting to the right, to produce more heat, NO, and O2. Isn't this right logic? I wouldn't know why it would not work.</p>
<p>Wait, did it say increase or decrease in NO2 concentration for choice III ?</p>
<p>If you have less heat, and the reaction is exothermic, the reaction shifts to the right, not the left, so NO2 decreases. Pressure does increase, but I'm not sure about volume...</p>
<p>Thus, raising the temperature of this system is equivalent to adding excess product to the system. The equilibrium constant therefore decreases with increasing temperature.</p>
<p>yes.. you are right.. then its II</p>
<p>since number of moles of gas increase.. therefore volume increases..</p>
<p>Yeah, HELTAHIR is right.</p>
<p>Is III increase or decrease NO2? I don't remember clearly.</p>
<p>Pressure decreases when temperature decreases...</p>
<p>but the problem stated that it was in a glass valve or w/e...meaning that volume is a constant..and since it was exothermic and heat was taken, away, pressure would decrease with the temperature (charles-lussac)....
i think choice III was that NO2 concentration DECREASES..
i put III only</p>
<p>It prob. did cause i also remember saying that it DECREASES</p>
<p>ok..so III only is right?</p>
<p>If we have the problem remembered correctly, then yes.</p>
<p>Lets Take A Vote:</p>
<p>(a) A only
(b) B only
(c) C only
(d) A and B
(e) B and C
(f) A and C
(g) A, B, and C</p>
<p>you mean I, II, and III right? i got c</p>
<p>Lets Take A Vote:</p>
<p>(a) I only
(b) II only
(c) III only
(d) I and II
(e) II and III
(f) I and III
(g) I, II, and III</p>