<p>Find the arclength of the curve at the given interval</p>
<p>0≤θ≤π/2</p>
<p>x=r(cosθ+θsinθ)
y=r(sinθ-θcosθ)</p>
<p>Take dx/dt, dy/dt, and square them both. Integrate from 0 to pi/2 of the square root of (dx/dt)^2 + (dy/dt)^2.</p>
<p>Yeah I realized that’s what to do. I was going crazy because I thought it was something weird like a polar within a parametric…</p>