<p>Can someone break it down? I'm soooooo lost.</p>
<p>give a specific problem, and then I might be able to help :)</p>
<p>N (sunscript 2) 3H (subscript 2) yeilds 2NH (sunscript 3)</p>
<p>What do you need found in that question?</p>
<p>lol sorry</p>
<p>What volume of NH (sunscript 3) is produced if 25.0 g of N (sunscript 2) is reacted with an excess of H (sunscript 2).</p>
<p>(25g N<em>2)/(14*3g/ mol N</em>3)=.6mol N<em>3 (14 is the molar mass of Nitrogen, and the subscript is 3 so we multiply)
N</em>3 +3H<em>2--> 2NH</em>3
Thus the ratio of N<em>3 to NH</em>3=1:2 (the coeficients.) Therefore, there are .6<em>2=1.2mol of NH_3. 1 mole occupies 22.4 L at STP. Thus there are 1.2</em>22.4=27L (note: i did heavy rounding) Is this coorect?</p>