That Math Section was Beast

<p>The log one was A i think.</p>

<p>When you subtract logs from each other it's the same thing as dividing them.</p>

<p>ex.</p>

<p>log(a-1) - log(b-1) = log(a-1)/(log(b-1)</p>

<p>Also, on previous ACTs and practice tests I usually have 20-25 minutes left when I'm done. I literally went up to the last second on this test. Of course there is always going to be a test day anxiety that will slow the process down, but this particular test was quite hard. </p>

<p>The last question, was it J?</p>

<p>^I'm so glad my precal teacher went over the log stuff considering logs was the last thing we did last year</p>

<p>Yup. The last question was definitely 2cscx. I think it was J.</p>

<p>Wow I think I picked that one... lucky me. Man, I'm really lucking out on some of my guesses, but then again, they were educated.</p>

<p>i guessed on 50% of the math test... lol</p>

<p>ugh i failed miserably...so annoyed. got a 29 last time but i guessed on 10 cuz i ran out of time and was expecting a lot worse score. i guessed on like 3 this time, but i think i made a ton of careless mistakes on the others:(</p>

<p>For the majority of you that have taken the ACT before, has this been the hardest math section you've ever seen? Just wondering because it was my first time today and I went crazy. I usually finish at least with 5-10min left on practice tests and I didn't even get to finish today.</p>

<p>sweet. I had to guess on the last one. Here was my thinking process. </p>

<ol>
<li>ignore the trigonometry</li>
</ol>

<p>sin x = x cos x = y</p>

<p>so you have (x/1-y) + (x/1+y) </p>

<p>therefore it should equal 2x. or something like that</p>

<p>2cscx was the only thing that was close to that.</p>

<p>omg it was tough, i had to guess on about 4-5 omgomgomgomgomgogmgomgomg</p>

<p>heres the real way :P</p>

<p>sinx/(1-cosx) + sinx/(1+cos)
Common denominator:</p>

<p>sinx(1-cosx) + sinx(1+cosx) / (1-cosx)(1+cosx)</p>

<p>Simplify and identity:</p>

<p>sinx(1-cosx + 1 + cosx) / (sinx)^2
2sinx/(sinx)^2 = 2/sinx = 2cscx</p>

<p>What I did was just set my calc to radians set a degree for x... i made it 65 or something and i tested all of the answers and got 2cscx (or it was just that none of the others worked...)</p>

<p>i thought the banquet one was as simple as it looked. i just skimmed through the stuff cause i didnt have time... but i think it asked how many people would be at the banquet and it gave numbers for all three sports</p>

<p>i think you just add those up because im guessing that when it said the people who did 2 and 3 sports were already counted in participating in the one sport</p>

<p>i think i got 83 </p>

<p>but im not sure on this one</p>

<p>the banquet one was 55, cuz you have to subtract the people who were counted twice. and yeah, i thought this time the math section was kinda hard...</p>

<p>I got 70 for that question, however ppl don't seem to be getting that.
On the last question, I actually thought it was one of the easiest questions on the test. All you had to do was plug in a value for x (degree) value..plug it in..and see which answer choice was right. On84..I idnt know how to input the last choice but still knew it was correct cuz nothing else was right.</p>

<p>was 58 an answer chioce for the banquet one? I know one of the answer chioce was 2 more than the answer... </p>

<p>Anyone remeber what letter the answer was for the parallelogram question? I put D...</p>

<p>jckund, did radians work for you? I think I got your answer and used your same method. Actually I think I might have had it on radian but I think you only want to do that if you're graphing it, not if you're doing regular calculations. I thought I used degree though I really can't remember.</p>

<p>ya but they never said that they counted them twice</p>

<p>it just said x amount of people participate in bball, y amount in fball, z in track</p>

<p>what about the arc one dealing with the circle? God that one confused me..</p>

<p>I think that had something about the angle divided by 360 and then times the formula of getting the circumference.</p>

<p>For the parallogram,, it was like</p>

<p>(A) -4, ??
(B) -4, ??
(C) -4, ??
(D) -3 ??
(E) -3, ??</p>

<p>was it one of the -3's or -4??</p>