UNcoordinated dual degree?

<p>How difficult is it to pursue a dual degree in engineering and business without the M&T program? I am applying M&T ED, but if I don't get in and am bound to Penn SEAS instead, I wanted to know whether it would still be possible to pursue my goal of a dual degree in engineering and business. </p>

<p>I had a few questions regarding this:
- Is there a minimum GPA needed to add a second degree in a different undergraduate school?
- Is there anyway I can start working towards the second degree freshman year, or can I only add it later on in the process?
- Will I have to take more courses than the M&T students?
- Would I still have liberal arts requirements to fulfill in CAS (not that I don't like the humanities, but I think it would be near impossible to take a lot of these courses alongside 2 degrees)?
- Is the uncoordianted degree a more feasible option than trying to transfer into M&T?
- Are there people that regularly do this?</p>

<p>Help with any of these questions would be much appreciated! It is critical in helping me decide whether or not to list Penn SEAS as a backup. </p>

<p>If you google or go on Penn’s site, there’s a separate application for regular dual degree kids. There aren’t many per year that do SEAS + Wharton, last year around 18 got in. Something like 30 applied? Easier than trying to transfer into M&T. Yes you take more courses than M&T. You need to fulfill both school’s degree requirements 100% (including liberal arts requirements, hopefully you have some AP credit, otherwise more coursework) , using overlaps where possible. That still means around 50 credits, as opposed to ~40 for Engineering/Wharton/M&T. So many regular dual degree kids stay more than 4 years, or they have to overload, go beyond the 5.5 credit limit per semester.</p>

<p>To be frank, many people here are jealous of whoever’s in M&T, and dual degree is the second tier option. Still a very good option though, but getting in M&T will make everything easier for you.</p>

<p>tysm! exactly what i was looking for.</p>