2011 January SAT: Math

<p>so for that question the answer was 1/3?</p>

<p>One other question.</p>

<p>There was a geom question with a large square. I don’t remember too much, but there was a square with a side of 1, there was a point that was a midpoint. It was fairly simple, but I think I made a mistake. The answer I choose was (sqrt(3) - 1)/2. I’m almost certain I got it wrong, but I can’t remember the figures in the question to see what the answer was.</p>

<p>Everyone keeps asking about the 1/3 answer in the fill-ins.
I don’t remember word for word what the question was but it was something like the equation of a line was given and then you had a set of coordinates from another line that had the same slope, and it asked you for one of the values in the equation y= ax + b. I am fuzzy on the details but you had to subtract 2/3 from 1, which is 1/3.</p>

<p>@terebin</p>

<p>That one wasn’t experimental, I had writing experimental and got that question. The consensus answer is 50/51.</p>

<p>@silenex: It was [sqrt(5)-1]/2</p>

<p>rennir how do you do the (sqrt(5)-1)/2 problem</p>

<p>is 1/3 the answer to
The question said: If x is the average of the other two sides of a triangle, and the perimeter of the triangle is P, then what is x in terms of P.</p>

<p>altamash</p>

<p>you used one line’s info to find another, and then another (I can’t remember exactly), and you end up with (sqrt(5)-1)/2</p>

<p>okay what u do is use pythogoras theorum for half the side (1/2) and a full side (1) to get diaganol. that answer is root 5/(2). Then what you do is subtract 1/2 from that answer since the diagnol was equal to the side of the smaller square and half that of the larger one.</p>

<p>wait so did any of you guys get one with like two guys and shirts and budget?</p>

<p>@debater27: No, it was another one. But we got it already</p>

<p>JustAKicker, sorry but it is highly unlikely you will get an 800 with -1. It has happened before, but it is rare and I don’t think this one was difficult enough.</p>

<p>what about this one:</p>

<p>h is divided by 10 and remainder is 6
k is divided by 10 and remainder is 8</p>

<p>h+k divided by 10…what is the remainder?</p>

<p>what’d you guys do?</p>

<p>what u think this one was. im thinking -1 780. hoping for -1 790 or 800.</p>

<p>thanks , i messed up with pythagorean theorem, i ended up with (root(3)-1)/2</p>

<p>ohh! i know what you’re talking about now renirr, but do you still know if my answer is right?
If x is the average of the other two sides of a triangle, and the perimeter of the triangle is P, then what is x in terms of P.</p>

<p>is the answer also 1/3 for this one?</p>

<p>You could have guessed&checked. for example, take 16 and 18 as h and k. add them=34, remainder of 4. It is true for any h and k like 26 and 58</p>

<p>@Debater27 - Just substitute numbers in for h and k and it makes sense. Say h=16 (divided by 10 it gets a remainder of 6, as would anything ending in 6 really) and h=18. Together they equal 34, which divides into 10 three times with a remainder of 4.</p>

<p>So 4 is the correct answer.</p>

<p>@debater27: Well the answer is 4 because if you add the remainders together, you get 14. Just use two numbers ie. 18 and 16. I always use another set just to make sure the answer is consistent.</p>

<p>Anything divided by 10 has a remainder of its units place (ex: 18 / 10; r = 8). So pick two numbers, simply 8 & 6, 8 + 6 = 14 and 14/10 r = 4.</p>

<p>What kind of score (range) would I be looking at with 2 wrong 1 omitted.</p>