2012 AP Calculus AB Test Discussion

<p>I know the one you’re talking about and I’m pretty sure I did (0, e^(-3/2))</p>

<p>@John
I think the question explicitly stated “y=k” line…</p>

<p>I got (0,e^(-3/2)) for the concave down. The equation was 2lnx +3 = 0 for the second derivative.</p>

<p>I assumed it was a vertical line as well but realized it was horizontal in the last 10 minutes.</p>

<p>OK and then there was a question about…</p>

<p>A function that is STRICTLY Increasing
and integration from 1 to 5 equaling zero.</p>

<p>did you guys get something like (not exact numbers but similar)</p>

<p>f f(x)
1 -5
2 -2
4 6</p>

<p>pkim850 yeah that’s the answer I picked for that one</p>

<p>@2pkim850
Yeah, I think that’s the one that I chose. The other answers wouldn’t have made any sense, I don’t think.</p>

<p>Also: I’m pretty sure that the question also said “the horizontal line y=k”, because I was about to make that same mistake</p>

<p>Think I put B for that one because the function went from below the x-axis to above the x-axis, which could make the integral equal zero. Choice B was also increasing, so everything checked out.</p>

<p>Yeah, that’s right. The others either didn’t increase the whole time, or had all negative/positive values so the integral couldn’t be zero.</p>

<p>3----->0
4----->0
7----->0</p>

<p>Anyone remember choosing that answer??</p>

<p>What about the mean value theorem where c=4? It said to find the derivative at x=4. I totally forgot.</p>

<p>@karatekid666 That answer is wrong because the function is not strictly increasing.</p>

<p>OK please pardon my flood of questions</p>

<p>There was a problem about temperatures (during 20 minutes of time)</p>

<p>f(x) being the temperature at x</p>

<p>Is the integration from 0 to 20 of f(x)</p>

<p>the CHANGE IN TEMPERATURE or the AVERAGE CHANGE IN TEMPERATURE…</p>

<p>my friend and I were debating on this problem.</p>

<p>Karatekid it couldn’t have been that answer because in the problem it stated that the deriv was always greater than 0 or something like that but I remember it couldn’t be 0</p>

<p>@karatekid</p>

<p>I think it said y’>0 so that couldn’t be an answer.</p>

<p>**** 10charrr</p>

<p>Just the integral is the change in temperature.</p>

<p>what was the answer with the sin and cosine function? all i remember is the last two choices were 5pi/4 and 7pi/4. i got 7pi/4</p>

<p>It’s the change. If you look at actually solving the integral, it’s F(20) - F(0)… which also happens to be the final temperature minus the initial.</p>

<p>integral of that would be total change in temp it would have to be divided by 20 to be the avg change in temp</p>

<p>@Sydnekit</p>

<p>Wasn’t it just the slope from like x= 1 to 5?</p>

<p>It was E, 7pi/4.
pkim850, I had no clue. I put 2.8.</p>