<p>Plug in choices UVA:
x=3
B=8</p>
<p>|x-1|<b |3-1|<8=“” 1-3=“”>8, NOOOOO</b></p><b |3-1|<8=“” 1-3=“”>
<p>3-1<8
1-3<8</p>
</b>
<p>would you switch the signs if you take the abs to the other side?</p>
<p>damn it I’m watching chances of a good score slowly drift off. On my last 4 pratice tests I’ve gotten 33+ on all math sections now onthe real thing I get a freaking 30! NO</p>
<p>UVAorBust-</p>
<p>(from: [Absolute</a> value - A complete course in algebra](<a href=“http://www.themathpage.com/alg/absolute-value.htm]Absolute”>Absolute value. Absolute value equations - A complete course in algebra))</p>
<p>Example. Solve for x:</p>
<p>|x − 2| = 8</p>
<p>x − 2 is the argument. Either that argument will be 8, or it will be −8.</p>
<p>x − 2 = 8, or x − 2 = −8.</p>
<p>@ Rival and UVA</p>
<p>I think the proper math is to do this:</p>
<p>abs(x-1) < B
means</p>
<p>x-1 < B and x-1 > -B
= x - 1 < B and 1 - X < B (don’t forget to swap the sign)</p>
<p>Do a quick plug and chug counter check: if 1 - x > B </p>
<p>Let’s say if x is -5 and B = 5. </p>
<p>6 > 5. Ok now verify abs ( - 5 - 1) < 5 6 < 5? FALSE </p>
<p>So don’t think you guys are right</p>
<p>edit: beat me to it</p>
<p>Exactly, thequestionmark.
It is one of the rules to solving absolute value inequalities. </p>
<p>|1-x| < B
for the first split, you just take away the ||'s…making it:
1-x < B
for the second split, and the one that tricks people, you have to take away the ||'s, make the opposite side of the absolute value negative, and reverse the sign of the inequality…making it:
1-x > -B</p>
<p>Solve from there.</p>
<p>Grrr, the 2 I guessed on were both wrong, I think. What was #59 where it said q varies directly with r^2, what does q vs r look like, it would be a square root function right? If it isnt I got a 34, if it is I got as 35. Oh well, pretty decent for a first timer.</p>
<p>Man i screwed up math so hard
What do you guys think 6 wrong in math could be?</p>
<p>Hi, I know you guys might not remember, but was the answer to the last question choice D?</p>
<p>36-6= 30?
Right?</p>
<p>yes it was don.</p>
<p>Was was the letter choice to the Absolute value question?
A?</p>
<p>@ mabsjenbu123
Yes</p>
<p>@UVA
28-30</p>
<p>@questionmark </p>
<p>thanks for clarifying that.</p>
<p>I just realized that I think I stupidly made a mistake while doing the perimeter with the length double the width question.</p>
<p>P = 2(x) + 2w
x = 2(2w)
P = 4w + 2w
-4w = -P + 2w
4w = P - 2w</p>
<p>I think I accidentally moved the 2w over instead of the 4w. Ugh, if I did!</p>
<p>4w + 2x = P</p>
<p>x=P/2 - 2w I’m almost positive that is the answer.</p>
<p>Anyone remember seeing something like this on the test?
If (x+y)^2 = x^2 + y^2 then …
I know I got stuck on two choices, but can’t remember which two. I think the answer choices were something along the lines of:
A. one is zero
B. they are negative
C. they are positive
etc.</p>
<p>^B was that they were both 0, that question tripped me up too.</p>
<p>I think the answer was that one had to be zero. Not positive.</p>
<p>Yep, one of them had to be 0, and that’s all.</p>
<p>i second that^</p>