<p>I am using the beloved Ti-84 Silver Edition. I don’t have any special programs. Is anybody else going program-less?</p>
<p>On the TI-84 plus you can find:</p>
<p>Integral value
Derivative value
Point of intersection
Polynomial roots
Line Tangent</p>
<p>I find it a lot easier to know all the shortcuts on my calculator</p>
<p>Oh my bad. you would need absolute value.</p>
<p>When you are trying to find distance, use absolute value.
When you are trying to find displacement, there is no need (displacement can be negative, while distance cannot be).</p>
<p>@risubu</p>
<p>I’m going programless. There’s really not much point I feel, you can’t use the calculator on half of the exam and collegeboard knows how to get around most programs. I used to have some programs a few years back, but collegeboard figured out how to get around those.</p>
<p>Does anyone have useful programs that could actually help on the exam? It’d be interesting to know… I use a TI-83 Plus - nice and simple.</p>
<p>[tksfd</a> - Tinychat](<a href=“Live video chat rooms, simple and easy. - Tinychat”>Live video chat rooms, simple and easy. - Tinychat) I created a chat room for AB crammers if anyone’s interested in just discussing calc and asking questions. I know somebody did this last year for APUSH and it was SOSOSO helpful.</p>
<p>No you don’t take abs value b/c it asks for total distance e.g. walk 2 steps forward and three steps back; total distance of 5, displacement of 1. Remember displacement is distance from zero.</p>
<p>so wait when do you use absolute value? i’m kinda confused when to and when not to :(</p>
<p>You use the absolute value when wanting distance or speed, displacement does not need absolute value…</p>
<p>Generic question about the exam: If you make an error in part A) of a free response question, but use that value to correctly calculate part B) of the same problem, do you still get credit for part B) ?
I know this is true for AP Chem, what about Calc?</p>
<p>^^ Yes, you will earn the points for Part B but it varies. For example, some problems count the integral as a point, limits as point, and the answer as a point. Say you got the wrong limits but somehow got the correct answer. You would earn 2/3 for part B of that question.</p>
<p>awesomeee, thanks!</p>
<p>@collegedreams29 absolute value is when they ask for TOTAL distance traveled rather than displacement</p>
<p>Any tips on how to prepare for questions like #28,89, and 90 on the 2008 MC <a href=“http://buenaparkhs.edlioschool.com/ourpages/auto/2012/4/24/41875431/2008%20Multiple%20Choice.pdf[/url]”>http://buenaparkhs.edlioschool.com/ourpages/auto/2012/4/24/41875431/2008%20Multiple%20Choice.pdf</a></p>
<p>UChalpz1:
28 A – f(6)=3, so f-1(3)=g(3)=6.
Use chain rule to find g’(x)=1/f’(g(x)).
g’(3)=1/f’(g(3))
g’(3)=1/f’(6)
=-1/2</p>
<p>89 E – think Rolle’s Theorem (I despise this nonsense). Basically, for it not to be true with the given information, it can’t be differentiable somewhere, i.e. f’(x) doesn’t exist at a point k.</p>
<p>90 A – f is concave down, so slopes are decreasing. Slope from 3 to 4 must be less than 2, eliminating B, D, E. Can’t be C because the secant line from 2 to 3 equals 2, but that’s what f’(3) equals, and slopes are supposed to be decreasing (so they can’t BOTH equal 2).</p>
<p>Review MVT and Rolle’s so you know the criteria for both (one is really just a more specific version of the other), your basic differentiation rules, and the relationship between f, f’, and f".</p>
<p>Guys, is Newtons Method on the exam?!</p>
<p>Anybody know how to use the nderiv function on ti 89 titanium?</p>
<p>is there an answer sheet for <a href=“http://buenaparkhs.edlioschool.com/o...e%20Choice.pdf[/url]”>http://buenaparkhs.edlioschool.com/o...e%20Choice.pdf</a></p>
<p>I get mixed up between using Average rate of change and Average Value</p>
<p>WHEN TO USE WHICH??? HELP ME</p>
<p>In Ti-89, F3 1 is easier to use!</p>
<p>To use the nDeriv function on TI-89:</p>
<p>On the graph of a function, press F5 -> 6 -> 1 -> hit enter, input x coordinate you want to find the derivative at, then hit enter again.</p>