@silverhawk5 after the abs max/min question iirc
How about someone put this up on a google doc or somethin?
So if I got like 37/45ish (low estimate) on MC, and like 43/54 on the FRQ, where does that place me??? I got 5s on all the practice tests all year so… I hope I’m still good.
Lol when i saw the volume problem i was like bitch, fuck no and skipped it,
But anyway, I got 109/60 for the avg radius and 22,090pi/400 for the volume… like idek
What did you guys get for the value of k for the mc
Also, which roman numerals were true?
@holyground YES 2209/400 thank god I thought I was crazy!
That’s like 20ish points above the minimum 5 so I think you’re good!
And pi.
I just said Roman N. I was true only. and K was i think sqrt 2/2 if thats the correct problem.
@silverhawk5 I got squrt 2/2 as well.
There was a question at the start that said the distance a particle travels is d = e^2t and it asked for velocity at t= 5?
My calc teacher was so great; he prepared us well, like I want to get on his wall of fame so…
The volume problem was easier than it seemed. It was just simple integration, with the integrand being the area of the cross section. But instead of multiplying by the height @Kelvas, you were supposed to multiply by dh.
I also got sqrt 2/2 for the k problem and “I only” for the roman numeral. Btw, can anyone confirm whether or not its “legal” for us to be discussing these questions even in this vague manner?
I didn’t even have a calc teacher. Selfstudied this in like 2 months…I really hope I do get a 5…
How is the test scored can anyone explain?
For the numerals I put III only? smh
@Aleksander Good point. We should probably stop until they actually come out. Just to be safe. Peace
damn i got both those wrong.
and lol my teacher has a wall of fame too
and probably not
Lol ya r we allowed to discuss this?
nope but like i dont understand why not. like dafaq can they not make new questions?
How is the numeral one I only. III only works too. it was integral (from 0 to 2) of f(x)
assume the antiderivative of f(x) is F(x)
then the integral would be F(2) - F(0)
III. integral (from 1 to 3) of f(x-1)
F(x-1)| (3 to 1) which equals F(2) - F(0)
i think it’s scored
mc correct x 1.2 + frq points
so its out of 108
i think…