Speed was slowing down signs were diffrent
@harsh98 I just made a number line for g’(x). Every place where the graph changed from pos to neg or neg to positive would be a possible extrema. Then I plugged all of those values into the g(x) formula to find the abs max/min.
BTW also took seminar today pm me with any questions if you want. And I have US tomorrow sigh…
H’(1) ?
H’(1) was quotient rule i forgot the answer choice reply it i might remember
@hungrypanda -3/2?
Was there a place where those two equations were equal?
I said yes but used some wacko linear approximation so I probably won’t get any points lol
Yes bc you could get a rate that was - and one that was + so by IVT the net rate has to be equal to 0 for some value of c.
@Chrysanthemum14 yes that sounds right
I said yes and by IVT theorem. But I didn’t think the explanation I had in mind would work so that’s all I wrote. But I found out that it actually would have worked.
they were equal at 2.3 no?
Watch everyone do horribly on funnel and colle board ends up removing the question lol
I don’t think it was worth more than 2 points for 1d right? Cause I bombed that lol.
Probably got like 5/9 on that question which frustrates me bc it was easier…
How many intervals did you guys put for the last part of the triangle graph?
I don’t remember there being 1/10 after I got 109/6 maybe I got 109/60. I srsly don’t know anymore smh…
The funnel frq was hard
@Chrysanthemum14 like was that an FRQ
I messed up bad on that cause it said g<0 so the graph u look where it was decreasing but i thought it was positive so