The whole do they count or do they not count isn’t something I’ve ever gotten a straight answer on… Some people I know and trust say they do and then it gets scaled down to 50, while others say they are just straight removed, so I honestly don’t know.
They take out 10 questions because they are for statistical purposes, you won’t know which 10 questions there going to take out and that is why you have to try your best on all 60. The 10 questions are just removed, if you had it right or wrong either way it won’t affect your score.
Free response are up
For the second FRQ on Form O, the question “Explain why the diagram on the left is the better representation for the bonding in fulmonic acid. Justify your choice based on formal charge”… What if you said a really vague answer like “The diagram on the left is the better representation for the bonding in fulmonic acid because the formal charge is the most zero on all the bondings.” Would that still net me the point?
@gkdudtlffj I’m not sure about that. I think the answer was more about how the formal charge wasn’t on the center atoms in the left diagram. The more stable the center atoms are, the more stable the molecule is. Also, there was a -1 charge for 2 atoms on both of the diagrams so I don’t think you would get the point by saying that.
What are the E values on the last question?
That would make sense, I guess I got that one wrong hopefully its not worth to much.
I got 0.44 and 0.07 for the Voltage question
I got .63 V and -.07 V for the cell potentials
Same @dewzeph and it’s right trust me
@YeungerMoney I know it’s right too 
our last covered lesson was electro.
Yeah I also got 0.44 and 0.07 volts.
Anyone know the answers for frq 4, the chromatography one?
It is 0.63 V instead of 0.44 because if you have to use the reduction potential where you can balance out the coefficients on the electrons.
You do not use coefficients in reductional potential
It has to be 0.44 and 0.07 volts.
The answer was dye C and dye A
Solve them out using Hess’s law and you will understand what I mean. I’m not saying you multiple the actual potentials but you chose the wrong equation for the anode. Sorry if I’m poor at explaining I’m bad with language.
Yeah for the chromatography, c was least polar since it traveled the farthest with the non polar solvent, showing it shared similar intermolecular forces (like dissolves like), and A was the unknown since it’s distance from the solvent start and front was proportionate to that of unknown dye (both were about halfway).
OK… I’ve got my key made…
On the E values, they are .63V & -.07V…
For the dyes, it is C & A.
For the formal charge question, you will have to specificially talk about the relative EN values and how the - charge should be on the most EN atom.