<p>I’m not sure if anyone took a form B here, however, I believe it is very similar. The MC was a breeze for me as well… hoping for a 45-50/70. Finished it 10min early and removed those random guesses with educated ones. </p>
<p>However, the FRQ turned out to be equally as hard as the MC had been easy
1,4,6 I’m confident about… 3, I didn’t answer at all, except for ticking some objects for the experiment (hardest, especially since we didn’t do any experiments in class as school does not have sufficient resources). Answered no.2 completely but I’m not sure if it’s completely correct (most likely not)… and as to no.5, answered a,b,c and left the rest blank!</p>
<p>Tallying up a predicted raw score- about 45-50 MC, 40-50 FRQ… looking at how others felt it was hard too… I’ll be happy if I pass or even better a 4!</p>
<p>I said use a ruler to measure the slit, but I thought it couldn’t be that easy, so I got a few prisms to use as weights and hold the metal pieces steady.</p>
<p>@Mao lol we did this lab in class and all you need is a ruler to measure the distance between the fringes. If your talking about the two metal slits… you can’t just measure the difference between it, you have to calculate it because it’s pretty small.</p>
<p>I thought the test was pretty easy, well anyway because I have the best Physics teacher ever. I LOVE YOU MR.CAFIA. He is the best he thought me everything I know I would be surprised if I don’t get a 5 but some were kinds hard.</p>
<p>i thought we were asked to find only the voltage (electric potential) of the sphere…don’t remember the electric field part.
oh and also guys this is my very 1st AP exam…ughh i don’t know if we were supposed to put the answers in the green booklet or the white one??? :/</p>
<p>Also, for the question about the weight of the beaker, did you guys subtract the weight of the ball since buoyant force acted on it so it didn’t have its full weight value?</p>
<p>@yahooman1: on the list of constants, it said that g=9.8m/s2. Therefore, it was probably better to use 9.8 rather than 10 but as long as you were clear in showing your work, it should be fine. @isabelle94: answers were supposed to be in the pink booklet (the green booklet contains the FRQs + formula sheets and the white booklet is for MC)></p>
<p>the MC was a joke but *** was up with those frqs? 1, 2, 3 were easy then all downhill. My friend drew a charizard and said he ate the missing data-points on the “physical explanation” haha. You know the question.</p>
<p>Skorpius: yeah I did that, but none of my friends did. So i’m either a genius or ■■■■■■■■ (no offense to anyone)</p>
<p>gah i think i messed up the lab question…i set it up properly but i just said to measure the fringe length with a ruler and didn’t say anything about using the double slit formula…hwo much do you guys think i’ll score on that?</p>
<p>I don’t think you subtract the weight of the ball. That’s like saying if I’m holding a book and there’s something on the book, the total weight is less because of the normal force of the book on the object.</p>
<p>oh yeah it was pink haha physics blinded my eyes==
i thought it asked for the weight of the whole thing so i just added up every Fw: the weight of the beaker, water, and the ball…am i wrong?
oh yeah the single-slit experiment should we use m=1/2? Thanks guyz <3</p>
<p>The thing is if you put a spring scale and attach it to the ball, the ball will weigh less underwater due to buoyant force so the weight in the water would be less than outside the water…therefore the weight of the entire system will be less than what is thought to be true</p>
<p>Water displaced = Weight of ball, therefore the volume of the water in the beaker would increase and thus you can just calculate the total weight via (rho)Vg</p>
