<p>for number 1 is it okay if for the graph i made 6 bars, 1 for each category (boys w/ summer jobs, girls w/ summer jobs, etc.) and placed girl/boy bar of each same category next to each other and labeled it?</p>
<p>it shouldnt be an automatic 3 this is just 1/3 of one part of a problem that had 4 parts so its like 1/12 of the problem…dropping u to a 3 for just that is pure evil lol</p>
<p>HkB3, thats what I did for number 1, but its hard to show association that way.</p>
<p>Wait, 1/3 of what problem? the one i missed was the confidence interval one (number 4). Are you telling me we had to do conditions on another problem?</p>
<p>o sry thought u were talking abt number 6a still my bad</p>
<p>i get what you mean abt making 6 bars hard to show association but can they rilly tag u on tht?</p>
<p>hopefuly not (since I did that too because I was really confused about what to do). But everyone that I asked said they did the segmented bar graph. I remember 1b saying yuou had to use 1a to show what association. So if they count a right, i dont know what they will do with 1b.</p>
<p>6a had no conditions right? that would really suck if it did…because i didnt put any.</p>
<p>damn i was sooo confident i got a 4 on number 1 but now im not sure :"(
number one had no conditions…wut do u think the curve will be like?</p>
<p>^um wait i was asking about 6a? I didnt put any conditions, only number 4 i had conditions and i missed the nearly normal one</p>
<p>hopefully 68+ is a 5, 53+ is a 4…I think im about a 70 right now if i get a 35 on MC (which is probalby not going to happen)</p>
<p>ya nothing had conditions except for 4a for the 2 fire truck samples one</p>
<p>conditions=assumptions???</p>
<p>BTW , i used a double bar graph for number one as well. I don’t think they’ll take poi nts off. I mean, a double bar graph represents the data doesn’t it?</p>
<p>Esplin, this is from AP Central:</p>
<p>
</p>
<p>So wat were the conditions for number 4? What did we have to write down?</p>
<p>If I was correct in thinking it was a two-sample t interval…</p>
<p>Assumption 1: the two samples are random and from independent populations
Condition 1: given</p>
<p>Assumption 2: samples come from normally distributed populations
Condition 2: it’s reasonable to assume the populations are normally distributed because the SAMPLES are normally distributed, as the sample sizes are large (Central Limit Theorem)</p>
<p>There are other variations of assumption 2: one version is large sample sizes OR normally distributed populations; another version is normally distributed samples. I’m not sure if saying “the sample sizes are large” or “the samples are normally distributed” without mention of normally distributed populations would work. It may or may not. I can’t be too sure.</p>
<p>Oh yeah!</p>
<p>Except my teacher said to always assume taht the conditions are met.
I just put “assumed” after each assumption.</p>
<p>did anyone have the form b and figure out number 6 parts d and e… i got really confused because the inverse of natural log is the actual number… i didnt know what to do…</p>
<p>Bringing back this dead thread, but the scoring guidelines are online now.</p>
<p><a href=“Supporting Students from Day One to Exam Day – AP Central | College Board”>Supporting Students from Day One to Exam Day – AP Central | College Board;