<p>for 3c i actually got</p>
<p>y - 44 = 2(x-108)</p>
<p>is that right?</p>
<p>edit: o yeha, i remember getting 44 too.</p>
<p>what did everyone put for 3b</p>
<p>3b is def a local min.</p>
<p>relative minimum</p>
<p>dy/dx = (1+y)/x
int(1/(1+y))dy = int(1/x)dx
ln|1+y| = ln|x| + c
1+y = (e^c)(x)
f(-1) = 1
1+1 = (e^c)(-1)
-2 = (e^c)</p>
<p>Hence, y=-2x-1</p>
<p>part a of avg value of rocket = 199.something ?</p>
<p>Answers are here, people: <a href="http://users.adelphia.net/%7Esismondo/AP2006.html%5B/url%5D">http://users.adelphia.net/~sismondo/AP2006.html</a></p>
<p>neo , you are God. I love you. Let's make love.</p>
<p>Could someone please explain this:</p>
<p>"This particular simplification y + 1 = -2x would only be valid in the intervals x < 0 and y >=/> - 1. We know that x < 0 so we find what values of x would make y < -1 and exclude them. So, when is -2x - 1< -1 When -2x<0 which is when x > 0. So all values of x must be excluded if they are greater than 0.
Domain x < 0"</p>
<p>I've asked a few different mathy people who tell me it doesn't matter that the differential equation isn't defined at all points, and ergo they claim that the answer should indeed be y = -2x - 1. I'll try and ask more people...</p>
<p>For everyone who claims that the solution can't be linear because the slope field wasn't linear - they were screwing with your head. Graph it on like, 30 points. You'll see that any line plotted would be linear.</p>
<p>Damn it! I completely forgot to state the domain. I hate when I do that. Thanks for the answers though!</p>
<p>Can anyone see anything mathematically wrong with this set up to acquire my answer for the slope field?</p>
<p>Int(dy/(y+1)) = Int(dx/x))
ln|y+1| = ln|x| + C</p>
<p>Plug in our given values:</p>
<p>ln2 = ln1 + C
ln2 = C</p>
<p>ln|y+1| = ln|x| + ln2</p>
<p>y+1 = e^(ln|x| + ln2)
y +1 = 2e^(ln|x|)
y = 2e^(ln|x|) -1</p>
<p>Thanks for those answers, dude. Apparently I got around 4 2/3 out of the 6 FRQ's right. I missed the others out of sheer retardation (for example, subtracting wrong). If I got 6 or less (I know of 1 skipped and 2 wrong so far) MC wrong, is that good for a 5?</p>
<p>Of course it is.</p>
<p>i thought it was pretty easy....</p>
<p>p.s. Retina: thanks for that info about the slope field! that weirded me out too, but thats the answer i got...</p>
<p>yeah i didn't think it was too bad...a mistake on number one (gah) will only cost me a point, and then I'll be lucky for a 4 on number 3...the rest weren't too bad at all.</p>
<p>No prob guys.</p>
<p>yeah the answer to the differential was a line...weird. i kept on looking over the problem because i thought i got it wrong, since the slope is always -2 for the line, and the differential equation says it is y+1/x or something like that. its good that i got it right, though</p>
<p>yeah, my calc teacher was skeptical about the answer being a line...he'll have to take back what he said when we go over FR in class Monday (didn't have school yesterday).</p>