<p>Urgh, how much I wish the SAT was set up like the GRE - my cousin took it a couple of months ago, and since it was taken on a computer he was able to see his score immediately after taking the test. </p>
<p>I want to know my score now!</p>
<p>Im starting to see the logic behind the frequency question and x = 4… I think i might have misinterpreted the problem.</p>
<p>For the one in the xyz plane and perpendicular blah blah, is it possible that it could be 2? because did it ever say 3 dimentional or is it assumed? I figured only perpendicular from top and side.</p>
<p>still at my -5. hopefully thats all i missed and i make 800</p>
<p>Doesn’t XYZ itself imply 3D? That’s what I always thought.</p>
<p>exactly…the answer for that question might be infinite, I think</p>
<p>The question about x^2<4 what answer did you guys get
I forgot what I put but I think it was (0,2) or something like that</p>
<p>^that was a discrepancy</p>
<p>@Sunspark: I thought I put (-2,2)</p>
<p>^that was supposed to be the answer but wasn’t a choice. hence why it’s a discrepancy</p>
<p>Why is it (-2,2)?
because x^2<4 is actually -2<x<2 so wouldn’t x be 0 since it is in between -2 and 2?
I’m not dismissing your answer, TimXie I just want to know how you got that answer</p>
<p>wait… so what was the answer to the x^2<4 ?</p>
<p>i’m pretty sure it’s (0,2)</p>
<p>and does anyone remember the f(2)=-3 and f(4)= 6 and they wanted you to find x is f(x)=0 at only one location ?</p>
<p>geez…nope, I didn’t put that answer…</p>
<p>I know the domain should be (-2,2)
but I might not choose (0,2)</p>
<p>irun=3 kkkk</p>
<p>@irun4fun321 : I think that one should be (2,4)</p>
<p>and does anyone think the last answer was 1 point per question?</p>
<p>??
I thought it is 2…</p>
<p>A is 3, B is 2, C is 5…</p>
<p>but two of the scores were prime numbers… maybe i just made a mistake somewhere</p>
<p>Can someone explain the last one to me? I left it blank…</p>
<p>and can someone explain the points equidistant from two intersecting lines. i assumed it was an x-y plane, but i still wasn’t sure on the answer. i think i put a set of four points.</p>
<p>The equidistant points one used the distance formula. Swing the line like an arc and find the points where the line intersects (-x,0) and (x,0) then plug in values to distance formula and solve for x</p>
<p>@k2kankan :so wat’s the answer to that question?</p>