<p>@spratleyj: EPIC FACEPALM I was thinking about limits for a second. Discontinuity at x=2.</p>
<p>I got all real values of x, since (x-2) cancelled because it was in the numerator and denominator?</p>
<p>I got 4 for the ball question.</p>
<p>The ball one was 4 times you didnt even need to do 120 inches</p>
<p>even if you did 10 feet</p>
<p>10
4
1.6
.6
.256 (.256 ft is less than 6 inches)</p>
<p>Was the origin D or A? Someone please explain.</p>
<p>@markzilla, Which question are yout a talking about?</p>
<p>I remember getting all real values of x such that x doesnt = 0 or somthing as an answer.</p>
<p>Want the Vector question B? Quadrant 4?
Shouldnt the answer be B? (-dx + e questio)</p>
<p>@supernova ^ Lol I was wondering about that…</p>
<p>IT IS DISCONTINUOUS AT 2.</p>
<p>I don’t remember the problem, but I know there’s no way I missed it. We spent awhile on these types of problems at the beginning of the year in calculus and I’ve always been good at them.</p>
<p>If it was (x(x-2)(x-4)/(x-2) then it is discontinuous at x=2. I just tried it in my calculator too.</p>
<p>Yeah, I think I misread the ball one so it should be 4… For the -dx + e the answer was A!!!</p>
<p>@truzzi182: Yup. I was talking about limits so much I screwed up there haha.</p>
<p>Doing (x-2)/(x-2) is acceptable except when x = 2, where it would become 0/0</p>
<p>ORIGIN PROBLEM WAS A</p>
<p>AND REGARDING THE x-2 one</p>
<p>it is not FOR ALL REAL NUMBEr
IT IS DISCONTINUOUS AT x=2
becuase there is a hole</p>
<p>you cannot just delte the factor because you can do that in limit problem
but when they were asking about the graph
you can’t just simply delte the common factor and say it works for all points
if you graph it
u will see that at x=2 thereis no value and there is a hole.</p>
<p>Is anyone sure about #49 (perfect square)?</p>
<p>@spratleyj: question?</p>
<p>@spratleyj, the answer was 34.</p>
<p>You can reduce the exponents to simpler numbers and plug them into your calculator.</p>
<p>perfect square one</p>
<p>m^91+2m^90 what is m?</p>
<p>simple trick = m^90(m+2)</p>
<p>m can be any number because it is already square number</p>
<p>to be square, u need m +2 to be square, meaning m has to be 34</p>
<p>easy.</p>
<p>Find M such that m^90(m+2) is a perfect square… I got 34</p>
<p>im not talking about that, im talking about another problem.</p>
<p>The answer was abs(x) something and not equal to 2.</p>
<p>The vector was B though right? What is the x-2 question?</p>
<p>The K one was all real numbers except 0.</p>
<p>what was the answer to the one where you had to cut the box into two equal parts.
y=x+c. and they asked what c was.</p>
<p>the points of the box were (0,0) (0,4) (6,4) (0,6)</p>
<p>Also the one for x+c was c=0 for two congruent parts?</p>
<p>0 was the only on that cut exactly (0,0) since x+0=x.</p>
<p>okay, good that’s what I got 
Well thanks for confirming my answers - hope everyone did well…</p>
<p>no!</p>
<p>it is -1</p>
<p>x-1 cuts the rectangle into two parts…</p>
<p>That triangluar prism trough problem anyone?</p>
<p>I confirm lucky’s answer of -1.</p>
<p>@shahdin, I believe it was abs(f(x)) >= 2</p>