December 2010 SAT Math

<p>evilpanda, im not sure either but I believe it was asking for the points where x and y were BOTH positive</p>

<p>no it was clearly two. points D and F were both in qudrant I.</p>

<p>what was the question with 9:10 as the answer?</p>

<p>i got 40/7 for the 3x+4y question.
1320 for the rectangular prism one.</p>

<p>If I answered 5.71 (rounded to 4 characters) in the grid-in for the 3x+4y=40 one is that a wrong answer? Correct answer has been said to be 40/7 (5.71428571).</p>

<p>Also does anyone remember the answer to the one with the 9/5/9… one i said 1/5</p>

<p>i think it was 5</p>

<p>i did it all out and it canceled all the 9s and 5s except one 5 at the end so i think its 1/5.</p>

<p>for example (9/9)/5 = 1/5</p>

<p>How many integers satisfy the following</p>

<p>|x| < 5
|x| > 3</p>

<p>Was it two? (4 and -4)?</p>

<p>value of x for median with 2 lists and one was 2x and one was x; x=5?</p>

<p>it asked for the 7th term. you only found the 4th</p>

<p>@iceberg i got 6 on that one and i think one of the numbers was negative</p>

<p>nah 5.71 should work perfectly fine.</p>

<p>for the one where n+1>0 4-n<0 (or something like that) was the answer 7 possible numbers?</p>

<p>did sb remeber the question which need u to solve the n and 2n insert the two sets of the numbers,then they can have a same median?</p>

<p>@pink that was just an example of why i think it was 1/5 and not 5</p>

<p>the 7th term was like 9/9/5/9/9/5/5/5/5/5/9/9 (can’t remember exactly, but canceled out to be 1/5)</p>

<p>^^the answer to that one was 2.</p>

<p>@snoopi i got seven also now that i think about it, -2,-1,0,1,2,3,4</p>

<p>The 9 and 5 question was 5 and the n+1>0 4-n<0 was 7</p>

<p>just a quick q, but are sats superscored automatically? i already have 800 math so my main focus points were really reading and writing…
and colleges can still view ALL sat scores, correct?</p>

<p>How many integers satisfy the following</p>

<p>|x| < 5
|x| > 3</p>

<p>How is this 6?</p>

<p>What six integers were u thinking of?</p>