<p>the inequality was greater than or equal to
with the intercept at y=1</p>
<p>@hellomrkitty- I said “Never mind” in my previous post because I misread the question</p>
<p>3x + 4y = 40, since x must be less than or EQUAL to y, u can substitute y for x, which will give the greatest value that x can be. so 3x + 4(x) = 40, 7x = 40, x = 40/7</p>
<p>@evilpanda</p>
<p>I put those answers as well. I’m almost 100% certain that they are correct.</p>
<p>The circle in a triangle in a circle was 100pi because the radius of the small circle was 5 and the triangle was equilateral so the radius of the big circle was 10. With that in mind A=pi r^2 which came out to be 100pi! </p>
<p>As for the inclusive 1-1000 problem. 1000+999/1000-999 = 1999/1 or simply 1999.</p>
<p>Anybody get the question (on the second to last page of the section, bottom left), that asked how many points fit the x>0 and h(x)>0.</p>
<p>What was the answer to that one?</p>
<p>I put 2, couldn’t decided between 2 or 3 :(</p>
<p>parabola was def experimental
Ge231Fb what was the circle question i said 5,5 wasn’t on circle, so i think that was the answer?</p>
<p>It didnt say integer so x couldnt only be 4. I got 5.71 through plug ins. WOHOO</p>
<p>No, im pretty sure (6,8) wasn’t on the circle because (5,5) would be on it between (10,0) and (0,10)</p>
<p>yeah i had math exp.</p>
<p>(5,5) isnt on the circle. THe formula for the circle was x^2+y^2=100 and (8,6) works so yea.</p>
<p>I don’t remember it saying x ≤ y…oh well</p>
<p>@PulpoPaul</p>
<p>I put 3 :. I was also teetering between 2 and 3.</p>
<p>@cheng, Aww man. there goes my 800.</p>
<p>edit: nvm</p>
<p>10char</p>
<p>-Pulpopaul … i believe i put 3…(not 100%) but the answer is how many dots were in quadrant 1… (it mita been 2, i juz dont remember xD)</p>
<p>@fish- (5,5) wasn’t on the circle, which is the answer</p>
<p>wasnt the sa question 200?</p>
<p>and what many sides on a cube had 2 face,</p>
<p>what was the number of diff combination for 12 and 6</p>
<p>Zedwhy did you have experimental math or not? Did you have a question asking you what would be the angle in the triangle. The answer was X. Or did you have the inequality one with the parabola.</p>
<p>blue, If by the parabola one you mean the y >(or equal to) x^2+1. Then I had that one. I don’t recall having the angle in the triangle one.</p>
<p>@
fisa. Were you talking about the (-2,n) (-1,2n) 3<n<4 open ended before? I don’t think it said that k had to be a positive integer.</p>