<p>would anyone like to organize all the answers on this thread into one post...</p>
<p>So far this is what has been discussed:
1. Using the Chinese Calendar, what was the animal in 1776?
Answer: Monkey
2. Where b is a positive constant, when will a^2>b^2?
Answer: (-infinity, -b) and (b, -infinity) - () mean that the dots were not colored in
3. What will unknown side of a trapezoid be when the other sides are 40,45,50?
Answer: between 40 and 45
4. Arrangement of the photographs on an 8x11 sheet of paper
Answer: One vertical regtangle and one small square left uncovered
5. How many theather seats willbe left over?
Answer: 39
6. Law of cos/law of sin
Answer: everthing under the squareroot- Answer choice E
7. How many hot dog sold based on number of vendors
Answer: (30+x)(80-2x)
8. Triq question on boats
Answer: 45 degrees west of north OR 45 degrees east of south although most people agree with the first choice
9. Range of 2sin(x+3)+1
Answer: -1 to 3
10. How many gallons of paint needed to paint the diamond on the wall?
Answer: 6</p>
<p>for the second question on the list...
were there two choice that had -b to negative infinity and b to positive infinity....with one answer choice including -b and b and another not including -b and b in the solution set</p>
<p>oops, i meant to put -1 to 3, not -1 to -3</p>
<p>@Twaan: I think that there was one answer that included -b and b and one that did not include it. I believe that the correct answer was the one that did not include -b and b.</p>
<p>i put D...</p>
<p>i dont remember there being two identical line graphs..are your sure there was??</p>
<p>No I'm not completely sure. I didn't really spend that much time on that particular question as I was running out of time. Does anyone else remember that question exactly?</p>
<p>
[quote]
10. How many gallons of paint needed to paint the diamond on the wall?
Answer: 6
[/quote]
</p>
<p>Yesssssssssss...I'm pretty sure I guessed 6 even though I wasn't exactly sure how to figure it out. Well, wait...I may have understood the question--I can't remember. But I think I answered 6.</p>
<p>I do not think #2 is correct</p>
<p>I awnsered I think A which was 4...whatever choice was least...can anyone explain? because i split the diamond into 2...and got 4</p>
<p>Moose, a^2 will be greater than b^2 when |a| > |b|, which is precisely when - infinity < -a < -b or a > b...</p>
<p>For the one with the paint.</p>
<p>It is def 6. Easiest way to solve was plug in some variables. they said the paint for the square was 12. So make the length 3 and the width 4 (Doesnt matter) then solve for the two triangles. 1/2 B X H. Then multiply the triangles by two. You should get six.</p>
<p>I thought it was like (-1,1) because when you square those variables, you will always come up with a smaller number and b would be less than a
but F$#@!</p>
<p>What did you guys get the question about like the square had 7 units and a point was something like -1,4 what would another point be. I forgot the exact numbers so take this with a grain of salt..</p>
<p>wat is the answer to the second question on the list??</p>
<p>-1,11</p>
<p>it seemed like the most obvious choice
i didn't even check the rest of the choices</p>
<p>dnlagao, I don't remember the exact answer, but I remember that it was either the last or the second to last, and I remember my reasoning. Basically, you needed to look for an answer where the absolute value of x1 - x2 was 7 and y1 = y2, or the absolute value of y2 - y1 was 7 and x1 = x2, or both differences were 7 units. For example, imagine a square whose sides are 7 units in length and which has a corner at the origin, (0, 0). Then the set of points describing the square must be either {(0, 0), (0, 7), (7, 7), (7, 0)} if the square is in the upper right quadrant, {(0, 0), (-7, 0), (-7, 7), (0, 7)}, etc. Notice how in each case the above condition holds.</p>
<p>Are you sure? because when b is between -1 and 1 it is just going to be smaller when squared and then less than a</p>
<p>Not if -1 < a < b < 1</p>
<p>The expression was a^2 > b^2, you are assuming that the above condition couldn't hold.</p>
<p>for that one. I just found one of the points that added 7 to either x or y variable. Only one had added seven to one of the two. so i picked that one..</p>
<p>i think it was (-1, 11)</p>