<p>One quick and simple question. How do I solve this equation=</p>
<p>the square root of x-6 (minus -) the square root of x (is equal to)= 4
a.) 121/16 b.) 11 c.) no solution d.) 484</p>
<p>I think it's C... maybe A, but i don't know because I HATE fractions, lol. Thanks for all the help, guys. All I was told is to square the entire left side, and then of course the right, to get ride of the square roots... I don't know...</p>
<p>Rewrite it as sqrt(x-6) = 4 + sqrt(x)
Square both sides: you have x-6 = 16 + (2)(4)sqrt(x) + x
or -22 = 8 sqrt(x)
Square both sides again: you have (121)(4) = 64 x
or x = (121)(4)/64 = 121/16</p>
<p>Voila...</p>
<p>thanks 10^6 . ;)</p>
<p>easier solution. if you have ti 83 then type in the equation. then sto the answers for x until you get a valid equation.</p>
<p>Or put the equations in Y1 and Y2 and then do a 2nd - Calc- Intersect.</p>
<p>Yep. I have a T-83 === Thanks for the tips. ;)</p>
<p>isnt the answer c?</p>
<p>the sqrt (x-6) must be smaller than the sqt(x) -- so sqt(x-6) minus sqt(x) cannot equal 4, it must be negative for any x</p>