<p>***? Fall back?</p>
<p>what is that? stop being a tightass man some people just don’t do well on tests as everyone else.</p>
<p>^
ahh i think you read his post wrong or something…?</p>
<p>CC sensors some words i think…
and he said:</p>
<p>
</p>
<p>and above your post
</p>
<p>i think you just misinterpreted what he wrote… lol
from how i read it, he was talking about the pencil and feet tapping (which can get annoying during tests)</p>
<p>People asked how I do it so I’ll just post it here.</p>
<p>This strategy only works if you are fast with the calculator - you can’t use it on every problem because this method can be time consuming.</p>
<p>Before you start, read the problem and see it its primarily an algebraic problem (i.e. it gives you an equation and wants a straight-up answer, or its disguised as a word problem but needs algebra to be solved). If it isnt, dont use this method. If it is, try to see if you can solve the problem WITHOUT using this method. If its an easy problem and you know the answer for sure, dont waste valuable time. If you still cant get it, proceed on.</p>
<p>First, for each algebraic coefficient, pick a different “test case” number. While a test case number can technically be any number not equal to 0 or 1, it is advantageous to pick small numbers to reduce the size of the problem. Dont assign the same test case number to separate coefficients - this may occasionally cause errors.</p>
<p>Once you select a test case number (or numbers), plug em into the problem, replacing each instance of the variable with its assigned test number. Once you have done that, there should be no more remaining variables. Then, do the arithmetic and simplify the problem down to a single number. (i.e. if you plug in 3 to 4x-5, simplify it down to 4(3)-5 which equals 7.</p>
<p>At this point, you know what the test case problem results in. So, the last step is finding the correct answer test case solution, and therefore, the solution to the problem. Go through the multiple choice answers one by one, starting with A, and do the same thing you did above - plug in the test case numbers where appropriate and simply. The correct answer to the entire problem is the test case answer that is equivalent is the test case problem.</p>
<p>Sample problem:</p>
<p> x√4 - x√9 = (√ is the square root sign)</p>
<p>A. -5x
B. -x√5
C. -x
D. x
E. 3x</p>
<p>This is actually a really, really simple problem. The square root of 4 is 2 and the square root of 9 is 3, so all this is asking is “2x-3x =” </p>
<p>But, some people might have trouble recognizing it and might not be sure how to do it. Simple manipulation of the algebra makes it easy.</p>
<p>Plug 3 into the original problem, such that each instance of x = 3.</p>
<p>3√4 - 3√9</p>
<p>Just do the multiplication on the calculator (you still need to be able to recognize arithmetic operations, and the correct order they go in).</p>
<p>Simplification yields 6 - 9. The answer is -3.</p>
<p>Then, plug in 3 into all the choices that are given. The one that is equal to the answer you just got (-3) is the correct solution to the problem.</p>
<p>So it’s C), because plugging 3 into -X results in -3.</p>
<p>Sample #2</p>
<p>There are K gallons of gasoline available to fill a tank. After d gallons have been pumped, in terms of k and d, what percent of the gasoline has been pumped?</p>
<p>A) 100d/k %
B) k/100d %
C) 100k/d %
D) k/100(k-d) %
E) 100 (k-d)/k %</p>
<p>When you plug in numbers, make sure to use different ones. Try k = 4 and d = 2.</p>
<p>The hard part is figuring out what the problems equation should be.</p>
<p>Its asking you what percent of the gasoline has been pumped. Just reading the problem, 2 if half of 4, so youve pumped 50%. Now, you just have to plug in k and d into all the possible answers until you find the one that equals 50%.</p>
<p>A is [100(2)/4]% = [200/4]% = 50%. So A is the correct answer here.</p>
<p>Now, the caveat is that this method is slower than conventional problem solving. So dont use it on every problem because you will otherwise run out of time. But you should still use it on problems you dont know.</p>
<p>790 writing
700 reading
780 math
= 2270</p>
<p>major = neurosci</p>
<ol>
<li>My GPA was somewhere around 4.2 and I didn’t do all that much in high school. Might’ve been luck. Whatever.</li>
</ol>
<p>1940 SAT. 30 ACT. 4.3. ehhh</p>
<p>SAT: 1950
Reading: 690
Writing: 670
Math: 590 (hate hate hate math)</p>
<p>690 on U.S. History subject test, 750 on English Lit</p>
<p>ACT: 29</p>
<p>My scores were a little below average, but I think my GPA (4.3), extracirriculars and essays helped me out. I also took the SAT twice, and the first time my reading and writing scores were 40-50 points higher, but I had an embarassingly low math score. I took it again and improved my math and composite score, but my reading and writing scores suffered, which kinda annoyed me. But hey, I got in, so it’s all good :)</p>
<p>2290 sat 1
math 750
cr 800
wr 740</p>
<p>math 2c 790
bio m 800
us history 720</p>
<p>aw shiet we both got 800s on bio. lol i was planning on doing M all along, but i flipped to the M part and there was a question i didnt know so i was like **** it im doing E. go hard or go home!</p>
<p>sat 1: 2200
math 750
wr 800
cr 650</p>
<p>sat math 800
sat chem 770
sat phys 750
gl</p>
<p>SAT: 2010 (can’t remember sub scores)
Subject Tests:
-Math II 760
-Chemistry 740</p>
<p>Average/Below Average I guess.</p>
<p>sat 1750 act 25, i sucked so bad on the tests but my gpa was high so idk.</p>
<p>2210/3.7UWGPA</p>
<p>****ed around every day except for test day(s)</p>
<p>after seeing that the average sat score is ~2000, i really wish i didnt work my ass off :(</p>
<p>SAT: 2100</p>
<p>subject tests-
korean: 790
english: 750
us history: 730</p>
<p>i took another subject test… but forgot which one it was lol</p>