Hardest Math question ever

Test Preparation SAT Preparation
1

<p>It was in october 2009
number 19 section 2
It was a graph line with angle 30.
it says solve the equation of line l.</p>

<p>a) y = x\2
b) y = x\root 2
c) y= x\root 3
d)y= (root 2) x
e) y= (root 3) x</p>

<p>try to solve it guys</p>

2

<p>c. Look at a diagram of a 30 60 90 triangle. The ratio of y/x =1/ sq root 3 so y=x/sq root 3</p>

<p>This may just be a piece of info you’re supposed to know.</p>

<p><a href=“http://www.biology.arizona.edu/BioMath/tutorials/Trigonometric/graphics/trig_30_60_90.gif[/url]”>http://www.biology.arizona.edu/BioMath/tutorials/Trigonometric/graphics/trig_30_60_90.gif&lt;/a&gt;&lt;/p&gt;

3

<p>Or you could just write: y=mx where the slope m = tan(30)</p>

<p>That’s a useful little fact - a connection that many students (and teachers) fail to make:</p>

<p>If you know the angle a line makes with the horizontal, you can find the slope by taking the tangent of the angle. It works because tangent = “opposite over adjacent” – but that’s just another way of saying “rise over run”.</p>

4

<p>Um, easiest question ever. I know that there’s no trig in the SAT I, but tan x = slope of the line. So tan 30 = 1/sq.root3 = slope, so y=x/sq.root 3.
C
Or if you want to go the official SAT method (no trig), use the above poster’s method. It’s really not ‘the hardest SAT question ever’ by any means.</p>

5

<p>it was 2010 and yes just use tangent</p>

6

<p>

</p>

<p>I remember this question when I took the October 2010 SAT. :)</p>

<p>When you see something like 30<em>, 45</em>, 60<em>, or 90</em> a bell in your head should go ding ding ding during the SAT because this is a special triangle. The SAT loves special triangles. Make sure you know how to recognize not only their angles, but also their sides like x, x sqrt 2, x sqrt 3, and 2x.</p>

<p>From what I remember the line was a linear line (not curved) that started at (0,0). I may be mistaken. </p>

<p>What is the equation of a linear line? y = mx + b. In this case if I recall correctly no y-intercept so no “b”. Your equation should be y = mx. You simply need to find slope.</p>

<p>Opposite of 30* is = x. The adjacent side is equal to x sqrt 3. Plug into the equation:
y= mx.
y = (x/xsqrt3) * x –> Simplify (remove the extra x’s in the fraction)
y = (1/sqrt3) * x
y = x/sqrt3</p>

<p>Answer = C.</p>