<p>I wanted to major in computer science, but I got accepted into the Electrical Engineering major at UCLA. I want to do both EE and CS, and I understand that I can pick a CS pathway at UCLA, i'm just wondering how different the EECS program at UCLA is compared to the full on CS program. I want to work for companies such as Space X or Google, and I know they hire mostly software engineers. Also, I just love the whole concept of programming. I'm torn. I'm still waiting to hear back from Berkeley and University of Washington's Computer Science Program. If I get an undergrad degree in EE with a pathway in CS, can I get a master in CS? </p>
<p>Congrats! Yes you can, that will likely be no problem for you. Go online and look at the requirements for each major. Also you will have electives you can likely take extra CS coursework.</p>
<p>Thank you! I think I will end up doing that! I’m still researching though, hahaha. </p>
<p>Once you get into HSSEAS it’s quite easy to switch majors within, just switch to CS! </p>
<p>^seconded!</p>
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Once you get into HSSEAS it’s quite easy to switch majors within, just switch to CS!
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So the problem with taking anonymous advice on forums like these is that it might be wrong. Believe it at your peril.</p>
<p>What does “quite easy” mean? Well, the engineering department has a handy guide at <a href=“http://www.seasoasa.ucla.edu/undergraduates/change-of-majord”>http://www.seasoasa.ucla.edu/undergraduates/change-of-majord</a> Apparently “quite easy” means taking CS31 and CS32, two required math courses, and waiting until you’ve been at UCLA for 2 quarters. That page doesn’t say what GPA they expect from HSSEAS students, but it does say that students outside of HSSEAS must have a 3.5 in the engineering prep courses. Presumably they have some expected GPA for HSSEAS students, maybe even the same 3.5</p>
<p>Yes, “quite easy”</p>
<p>The process is simple, but it depends on how well you do in your classes. It shouldn’t be too difficult to do well if you manage your time wisely, but that’s up to you.</p>