Jan 2008 Math

<p>what was the question where the answer was w/2 because i somehow got w/3</p>

<p>no...the question specifically asks for the 20 miles...you didnt have to worry about time...and yeah its supposed to be hard...but if youre on this sight chances are youre pretty smart cuz you care about how you do...for most people i think that would be hard</p>

<p>it's definitely w/2, and i got 80/3 for car question.... avg velocity or something?</p>

<p>sandyrun, so whats the answer?</p>

<p>I got 80/3 at first b/c of the formula then I changed it at the last minute to 30 because I thought it made more sense. stupid me.</p>

<p>thats wrong cause x+Y+Z=w and if u plug in numbers 1 2 3 for x y z then look (X+Z+Y+W)/4=w/2</p>

<p>wasn't it average speed for an hour? also like carsonne said its #18 of 18 there not going to make it that simple</p>

<p>Sandy RUn...thank youuuuuu...thats what i was trying to say...it was the average speed for the 20 miles...not the whole time included thing</p>

<p>Mathleague.com says 0 is not an integer..."Positive integers are all the whole numbers greater than zero: 1, 2, 3, 4, 5, ... . Negative integers are all the opposites of these whole numbers: -1, -2, -3, -4, -5,"</p>

<p>i thought it was just asking for the average in terms of w
because the question was
w= x+y+z
wasnt it?</p>

<p>then mathleague is wrong.</p>

<p>shimshimhey...are you sure about the integer thing...cuz thats what i thought so i put 3</p>

<p>all i know is that this was a hard math one...the scores are gunna be higher cuz the relative grading</p>

<p>My answer was 30. Let's say both parts of the journey weren't 10 miles. Then you'd hafta weight the different portions of the trip depending on how long (distance) each portion was, not how long (time) it took to complete each portion. Using this same logic, we were lucky that they chose the same distance for both parts of the journey, giving equal weight to both 20 and 40, and making the answer 30.</p>

<p>It was just asking for the average in terms of w. The answer was w/2. Very simple... all you have to do is pick numbers for your variables. Just as moviemania explained it.</p>

<p>yes they were but if u know that when they ask for average of w x y z it means (x+y+z+w)/4 and if u plug in numbers for x y z then u can find w and then u can find average then u look at answers and plug w in and see which equals to ur average</p>

<p>yea lol its so easy no offense but thats how u do it lol.</p>

<p><a href="http://www.mathleague.com/help/integers/integers.htm%5B/url%5D"&gt;http://www.mathleague.com/help/integers/integers.htm&lt;/a&gt;&lt;/p>

<p>err.. but alot of people on yahoo said yes..
<a href="http://answers.yahoo.com/question/index?qid=20060908025929AAAmgqz%5B/url%5D"&gt;http://answers.yahoo.com/question/index?qid=20060908025929AAAmgqz&lt;/a&gt;&lt;/p>

<p>WTH WHY IS ZERO SO DEBATABE?</p>

<p>haha yeah i agree w movie mania...i cant believe everyones still arguing over that one...but yeah no offense...one of the really simple ones took me forever</p>

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<p>what they ("we") think is not right.</p>