<p>cool . . . thanks</p>
<p>umm… okay. back to math.</p>
<p>I got 80/3 too. The question was way too easy for a last question. And there was one question (s=3*n) and one of the answers was:</p>
<p>s (space) 3 (space) n </p>
<p>I was just staring at it! Good thing the correct answer was not mistyped.</p>
<p>Yeah me to!!!</p>
<p>Ok so have we reached a consensus here?
Answer to the Velocity question is 80/3 or 26.6 or 26.7
Answer to the small circle and 4 large circles is 0.414</p>
<p>i wrote D for the 4 circles one.</p>
<p>Yep. D was 0.414 i think</p>
<p>… yeah, but was it supposed to be the radius or diameter of the small circle??</p>
<p>Radius. There wasn’t even an option for .828.</p>
<p>and what were the given diameters of the larger circles?? </p>
<p>yeah, i know there wasn’t an option for 0.828 lol</p>
<p>well, the question is actually easy. the large circle has a radius of 1. therefore, the large square has a diagnosis of 4<em>1.414..after that, the radius of each circle forms a smaller square with a diagnosis of 1</em>1.414..one the large diagnosis, there are five parts-the diameter of the small circle, two diagnosis of the small square formed by large circle’s radius and two large circle’s radius. therefore, the diameter of the small circle is 2*1.414-2;and the radius is 0.414</p>
<p>the scores come in 3 weeks rite?</p>
<p>er, are you sure it wasn’t that the diameters of the larger circles was 1? so that the square would be 2*2?</p>
<p>fine, then, one way to figure out if i got it right or wrong: was the answer choice C?</p>
<p>idk I put C too, and if the diameter of the circles was 1 then I’m positive thats the correct answer but I can’t remember if it was 2 or 1.</p>
<p>Oh well guess I’ll just have to wait for my scores.</p>
<p>does anybody remember if it was x+y<x-y or x+y<y-x</p>
<p>The radius of the circles was 1, cause I remember the length of the square being 4.</p>
<p>^second that.
Connect the centers of the small circle and two large ones;
45-45-90 triangle with the hypotenuse = 2; each leg = 2/root(2) = root(2);
the smaller radius = root(2) - 1.</p>
<p>okay, whatever I put, it was choice C. I just don’t remember the number value at all… hahaha</p>
<p>did anybody get a question with painted yellow squares? it was a triple venn diagram thing.</p>
<p>yea can anyone say if it was y-x or x-y</p>
<p>Anyone want to compile a list of the answers we’ve come up with so far?</p>
<p>yeah that didn’t give information was cool one.. i thought about it and put it.</p>