<p>So, was the set one negative three or zero?</p>
<p>0</p>
<p>The test was ok IMO. SATs are not difficult, it’s the time constraints and the whole stress until you get to the actual test that make them hard. I skipped 4, prolly a few mistakes. I’m just banging my head against the wall for the StDeviation question. I thought there was ONE 8 in the set not multiple ones. Since standard deviation is undefined for 1 value, I put D. -.- I could get an 800 but probably won’t for the same reason I can’t get an 800 in the SAT I math: I can’t stop making stupid mistakes, no matter how much I know or practice. I got 800 on CR, 800 on Writing and by some miracle 700 on math. Hence the subject test to show that I’m good in math, and because unlike on the SAT I, on the subject test you can make mistakes and still get a good score. Hope for a nice curve</p>
<p>UGH. SO MUCH MISTAKES. :((</p>
<p>@MSJKID what about the table in which y was always 1/2? I put that y didn’t vary as a function of x because y didn’t vary at all.</p>
<p>Wait guys if you could remember, can you write down the question for the S1,S2,S3 M1… thing? I don’t remember but I don’t think I got that right.!</p>
<p>What do you guys think that the curve will be for this test?
Will 43/50 be an 800?</p>
<p>YES</p>
<p>@rdivate, from past threads, I think a 43/50 would be fairly generous, although not impossible. At this point, it’s only speculation, so I’d try to not worry too much about the curve.</p>
<p>That cos² question was clever, but I skipped it initially and came back to it. Time was called just as I got the answer. It took me ~5 seconds to figure it out (I’d done many problems similar to that one in Dr. Chung), but I didn’t get a chance to bubble it in :(</p>
<p>As long as one x doesn’t correspond to 2 y values, the relation is a function. If you plot the points and draw a vertical line through the graph,the line shouldn’t pass through 2 points. This will occur only when one x corresponds to 2 y values. The relation in which y was always 2 or 1/2(don’t recall exactly) is a horizontal line. If you draw a vertical line that intersects that line, it will intersect only one point. That relation is also a function.</p>
<p>For the set question, are you guys sure that you didn’t overlook a negative number in the final set? I remember that there was 0 and one negative number in the final set.</p>
<p>I don’t think there were any negative numbers…</p>
<p>I’m pretty sure that the perimeter of the triangle inside the cube one was 21.21 right?</p>
<p>The IQR is 50. I’m in AP stats, the IQR is the 75th percentile-the 25th percentile which 75-25=50</p>
<p>I thought it was jan every year because cos is 0 for pi/2 and 3pi/2 and cos 0 would give you the maximum</p>
<p>The IQR is 50. I’m in AP stats, the IQR is the 75th percentile-the 25th percentile which 75-25=50</p>
<p>I thought it was jan every year because cos is 0 for pi/2 and 3pi/2 and cos 0 would give you the maximum</p>
<p>I thought it told you how to calculate the IQR in the problem?</p>
<p>Yeah. You might be taking AP Stats but I don’t think that the method to solve this problem is what you talked about. </p>
<p>The answer to the cube was 2 root 50 plus 10 which is 24.14.</p>