<p>chronic i think i got 4/5 also....what was the question?</p>
<p>xcotter it was 10 for SURE, i put 7 too it's ok a 790 won't hurt ;]</p>
<p>omg its 10....3 was also in the intersection of the given points....just because the 3 was apart of the other intersection doesnt mean it wasnt apart of the asked intersections....they didnt ask "what is the number in the intersection with these 2 points WITHOUT being in another intersection."...point blank...its 10...</p>
<p>I agree with the whole 10 thing now.</p>
<p>yep it was 1/15</p>
<p>yes i did get 1/15 for the grid-in</p>
<p>but wasnt 4/5 also an answer? to question #2?</p>
<p>Dang it I hate these problems. lol</p>
<p>1/15 was a grid in and 4/5 was a multiple choice i believe</p>
<p>4+</p>
<p>as long as u can draw a diameter, u can fit the rectangle, and u can draw 4+ diameter, thus 4+ rectangle</p>
<p>yea chillin i got that too</p>
<p>An infinite amount.</p>
<p>you could get 4 +............... i put 4 only but apparently that was wrong</p>
<p>wow im dumb.............. i cant believe i put that</p>
<p>ughhhh stupid stupid stupid mistakes</p>
<p>......................................................</p>
<p>it's definitely 7.</p>
<p>the intersection of x/y includes the intersection of x/y/z. so the 3 is only part of the 7. like think of it this way. you have 7 objects in both x, and y, and then out of those 7 there are 3 who also fit the description for z. if there was 10, then they would have to write 10 in the intersection x/y region and 3 in the x/y/z region.</p>
<p>but did the question ask how many rectangles you can inscribe using any point of the circle? i thought it asked - "how many can be drawn using the points that are given" :/.</p>
<p>I love the controversy...</p>
<p>no its def 10</p>
<p>wendy it said intersection of Y and Z, not ONLY Y and ONLY Z</p>
<p>there had to be some sort of trick to that question or it wouldnt be on the sat</p>