<p>what is vanadium? i totally skipped that one!</p>
<p>yeah it was VO2.. the VO2 sample was 8.2 grams making it 0.1 moles</p>
<p>Yeah I put VO2...ok good</p>
<p>is vanadium an element? i've never heard of it before.</p>
<p>A transition metallic element with a#23</p>
<p>what exactly was the vanadium question?</p>
<p>how did you guys all know about it? it's like i've never heard of it before...ever.</p>
<p>if you have 5.1 grams of vanadium and its oxide form weighs 8.3 grams, what is the formula?</p>
<p>5.1 is .1 mole of vANADIUM and the rest 3.2 is 10% of 32 grams (the weight of two oxygen atoms).</p>
<p>so...nobody's posted in a long time, can anybody think of any more hard questions?</p>
<p>let's party</p>
<p>the one with HgS what is the coefficient in front of it?</p>
<p>Was it the coefficient in front of HgS? Was that what the question was asking for I mean? If it was, then it is one....if it was asking for the other thing you formed that was something like HI, it would be two because the equation is</p>
<p>HgI2 + H2S --> HgS + 2HI</p>
<p>I think it was:</p>
<p>HgCl2 + H2S --> HCl + HgS2</p>
<p>or something...can't remember..</p>
<p>^I think your equation is unbalancable
it should be
Hcl + hgs in products</p>
<p>I put 1 because it was definitely Hg(2) in the reactants since it was HgCl2. And since S is (-2), then the subscripts will cancel out so HgS and it does not need any coefficients.</p>
<p>I put 1 because I kept thinking about possibilities and everything I did seemed like it would reduce</p>
<p>oh yeah what was the answer to lab procedure question. the one aboutih pointing testtubes at others o_0...</p>
<p>85 to 78 = 800
77 & 76 = 790
75 & 74 = 780
73 & 72 = 770
71 & 70 = 760
69 & 68 = 750
67 = 740
66 & 65 = 730
64 & 63 = 720
62 & 61 = 710
60 & 59 = 700
58 & 57 = 690
56 = 680
55 & 54 = 670
53 & 52 = 660
51 & 50 = 650</p>
<p>Do you guys think this curve is accurate??? I don't know but doesn't it seem to be a little too generous...</p>
<p>Wow... from reading this thread i can just sense the 800 slipping away from me... lol</p>
<p>that looks pretty accurate...</p>
<p>for that test tubes one I said heating the graduated cylinder...because don't you not heat those?</p>
<p>does anyone else remember like 3 or 4 B's in a row in the second column</p>