<p>temperature is constant at phase changes…</p>
<p>Definitely CO2 for not harmful, we breath that in all the time…</p>
<p>NO2 is right for all having an unpaired. I have a list of like 15 other answers but I’m too scared of College Board to POST. =O I’ve pm’d it to people already</p>
<p>^ Hasn’t embargo been lifted already though?
Either way, can you PM it to me? (:</p>
<p>Hey can you PM it to me</p>
<p>charizarrd: Oh, that was a different shifting question. For that one I think I put adding more water because it would increase the solvent’s ability to dissolve solute (that was a saturation equilibrium). The other one was a gas equilibrium, the answers were like increasing heat (wrong because it was exothermic), increasing pressure (wrong because there were less moles on the right side), adding more reactant, taking away product, and decreasing the size of the container.</p>
<p>CRAP NANTUX! I think you are right… :(:(:(:(:(:(:(</p>
<p>grrrrrrrr didnt put co2. bleh.
jerseykid55 can u pm me too…?</p>
<p>no, at a normal phase change from liquid to gas (boiling) the temperature would stay the same, but evaporation is different, it occurs when random particles have enough energy to leave the state, when you get out of the pool, and dont dry yourself off, you feel cold, some of that is from the wind blowing perhaps, but it is also evaporation occurring.</p>
<p>the increasing temperature, increasing pressure one,
wasnt it increasing temp? cuz it was exothermic, if u increase temp it’ll shift to left
and ques was which would cuz it go toward left</p>
<p>jerseykid55 i’d appreciate a pm too</p>
<p>@sententia: Oh… I put HCl because I thought it would completely dissociate, meaning there would be more products, so the reaction would shift to the left? But then, your explanation sounds more reasonable, so you’re probably right…</p>
<p>No, if it’s exothermic it would favor doing the reaction more (and shift to the product)…</p>
<p>Temperature of the REMAINING water is not constant… as water evaporates into vapor it absorbs a ton of heat.</p>
<p>Which of these tools would be least useful?</p>
<p>Separating water and methanol?</p>
<p>pm por favor</p>
<p>Wait, why can’t jerseykid55 post his answers? D:</p>
<p>this is Jerseykids PM
the embargo has been lifted…</p>
<p>this is what i remember…
ink by distill (wrong)
water and ethifej (Distill)
sand and salt (filter)
h20 cryatal (hydrate)
H and metal (hydride)
Tin for more ox states
h20 add salt … you get lower freeze pt (right), higher density (i put false) so just III but i think it might be II and III
CO2 not harmful
7 carbon atoms (last question)
separate by evaporation (salt)
mendelev … T F
3 TT CE’s in a row in second column
only one TT CE in the first column
one TT CE was it was about evaporation and not having enough energy and they have less temp (ACTUALLY MIGHT BE FALSE
NO2 everything has an unpaired
hydrocarbon- organic</p>
<p>thats all i remember for now…sa</p>
<p>@sententia, you’re right about the evaporation one but not about the other one, take an equation X + Y –> Z + heat, if you add heat, there will be excess heat on the right side of the equation, and lachatliar(or however u spell it) says that the system will work to relieve that stress by using the heat, making more reactants.</p>
<p>Does anyone remember a question where it was like NaCl compared to H2O and I was it had a higher boiling point, II was that it had a higher density, III was it had a lower freezing point? What was the answer?</p>
<p>II and III Charizard</p>
<p>Tn or Zn on the first part?</p>
<p>Damn! I put II only…</p>
<p>@sententia: Wasn’t the least useful tool question for titration or something? I put bunsen burner…</p>