<p>Did anyone get j^4 = k^3 for one of the questions?</p>
<p>Can someone clarify this problem for me?</p>
<p>Square ABCD has an area of 40 and a length of 6. The width of the rectangle is 8. Which of the following is the volume of the rectangle?</p>
<p>I got 320, since height has to equal 6 2/3 and V=LWH, so (6)(6 2/3)(8) = 320, which was not a choice. I left it blank, but can someone tell me what I did wrong?</p>
<p>@goldysocks
it was something like y= -2x+k and y= -2x+something…what value of k would give infinite solutions or somthing like that…</p>
<p>Yes, j^4 = k^3 was definitely right :)</p>
<p>by looking at all the other sections that are posted, obviously every person had one of the three sections as experimental. is that a given, or is everyone supposed to have the same experimental section?</p>
<p>jollybjolly I did.
Circular: It was a rectangle. You had to find the lenght of one of the diagonlas, which was 10, so height was 4. So it was 4<em>6</em>8= 192</p>
<p>
</p>
<p>thought so and it was E i remember</p>
<p>@Circular. </p>
<p>The rectangle with an area of 40 was formed by the diagonal & the height of the prism.
Because the triangle is an 8,6 right triangle, the diagonal is 10.
This means the height is 4.</p>
<p>8 *6 * 4</p>
<p>@goldysocks and cribelle</p>
<p>Thanks. I made a really stupid mistake then…</p>
<p>^ since 6 and 8 are the dimensions are the base, its diagonal is 10, which is also the base of ABCD. So the height of ABCD is 40/10 = 4, which is also the height of the solid. So V = 6<em>8</em>4 = 192.</p>
<p>why is 192 ?</p>
<p>the height of the triangle was 4?</p>
<p>why is 192 ?</p>
<p>the height of the triangle was 4?
^
It asked for the volume I believe.</p>
<p>the diagonal is 10, okay.</p>
<p>The rectangle problem was pretty easy… I don’t know why there is like 3 pages of debate about it. The answer is 192… draw it out and it is quite easy to see.</p>
<p>Does anyone remember if -m was choice E?</p>
<p>i think it was choice D</p>
<p>Consolidated List -copy and paste! 36/54
Birds were 1/4 of the pets
(n+2)(n+3)/2
minimum of lxl-4 is -4
some divisible by 6
20 students question was I and II
72 degrees
2x+y was 104
6 X 8 X 4 = 192
number line was A
7/9 for pentagon in triangle
triangle in square 1/8
(0,a) 4x+2y=48-> 16
Pictograph of beach->C
c/b: 1/3
Chairs: 22
Triangle/square thing: 3sqrt2
90%/10%: 81
3 circles (AB=): 1
Some circumference thing: 10pi
Another circumference thing: 32pi
Slope of one side is m: -m
Temperature: 4.5
Four digit number: 9970
Phone: 6
g(0): 6
Systems of equations with infinite solutions: k=104
c+xb
x+1/y
Juniors and seniors: 2/3
The rectangle was 4 by 4.
3^n sequence: none
Parabola [a(X-2)^2]: 8
j^4=K^3
4 or 28
AB/NB is 11
5x+3=4x+6 is 3
if x+y= 240, then what is z? 60</p>
<p>Yes, for some reason, I feel it was choice D.</p>
<p>Okay, I think that’s what I put.</p>
<p>I misread the rectangle question and thought it said square, which is why I got it wrong
just a stupid mistake</p>