June 4 SAT I Math Only

<p>do u guys think it was harder than the math in may?</p>

<p>yes it was harder (on the hard questions) but otherwise the easy and medium questions were easier than may and that's why many people who got HARD ones wrong this time are saying the test was easy because they felt they did good on the majority of the questions.</p>

<p>I just set up a proportion, since the heights and widths of the two prisms were proportional.</p>

<p>phew...thank god. at first I was like ***? because I was about to use a prism formula lol...but then it hit me...and I just did proporting for what was given. They just had to use a prism didn't they!</p>

<p>ok I got 3/11 for that set problem and no one really replied to this one...so appreiciate it you could tell me what you did.</p>

<p>A = x number of stuffs
B = 2x
C = 1/4 of A + 1/3 of B = x/4 + 2x/3
C = 11x/12
so A/C (the percentage of set 'A' within C) = (x/4) / (11x/12) = 3/11</p>

<p>this was the question right? cuz I plugged in numbers at the time and it worked for me.</p>

<p>The problem where you had to reflect the triangle about the axis really bothered me, but I got it in the end i believe.</p>

<p>I didin't have that one...mind reiterating it?</p>

<p>anyone have the gridin answers stored on their calculator, not the exper. sec the real section</p>

<p>Could anybody with a math experimental, being on the 5th section, remind me of a couple of questions that were on that section. Thanks.</p>

<p>what were the answers to the grid ins??</p>

<p>find em, I know they have all been discussed.</p>

<p>I remember a question that said if the distance from A to B is 8 and from B to C is 6, which could not be a distance from A to C. At first I put 2, but I was thinking triangles and forgot that they could all be on one line. I ended up putting 15. Does anyone else remember getting this?</p>

<p>i didn't have this one...or maybe I did I forget. Was it multiple choice?</p>

<p>I would guess it to be 15, because anything higher than 14 couldn't work (14 can, because of the straight line, everything else is traingle inequality based).</p>

<p>also was 2 the lowest choice...other wise anything lower than 2 could not be the distance too for the same reason as above.</p>

<p>if 15 was a choice, then i guess 15 would be the right answer.</p>

<p>15 is the choice. think about it. The longest distance it could possibly be is if they're on opposite ends of a ray with B inbetween, which is 14. 15 is impossible.</p>

<p>does anyone remember the question that had a triangle in the first quadrant of a coordinate plane and one of the slopes was 1/2 and its area was 12. I think you had to find the length of one of the sides. Anyone remember what they got for an answer? Thanks!
~wallcaulliflower</p>

<p>bump...didn't have it but anyone care to help wallcauli out?</p>

<p>I got something with a 2root3, don't really remember....</p>