<p>i think it was 8x+4y=k, and jenna we are giving the answers for the international test which is not going to affect our curve because all regions where the international exam is administered have passed 8 o’clock.</p>
<p>Pfffff this thread isn’t going anywhere atm.</p>
<p>We need one of the guys who remembers every single answer and go them right to post on of those consolidated lists.</p>
<p>What did everyone get for Q8 in the grid in section. I’m quite sure it was E.</p>
<p>what was the answer?</p>
<p>Y^4=x^3 i thinkkk</p>
<p>That’s the j and k rightt yes its the last one I remember getting the last one. If j ^ 2/3 = k ^ sumthing</p>
<p>WHAT? The median one was D I II?
I got I II III.
It’s not greater than or equal to four?
If i got one wrong i wouldn’t have an 800 anymore right?
omgg… bye 800 
:(</p>
<p>I got E also on that question the median question i got I and II also!!
I hope i get a 750</p>
<p>(7/9)a
ab=1 (3circles)</p>
<p>I thought it was 8x+4y=k and 2x+y=26</p>
<p>agree with lwxted</p>
<p>@judakiss26 </p>
<p>8x+4y=26 and 2x+y=k right?</p>
<p>just multiply 4 to the second equation. lol easy like that</p>
<p>you will get 8x+4y = 104 which means the same equation hav two diff answers. so the prob cannot be solved. it is wrong.</p>
<p>104 = correct answer (pretty sure abt it)</p>
<p>what？ I thought that the median question was I. The median doesn’t have to be 4.</p>
<p>yea I just multiply 4 to 26 = 104.</p>
<p>I think the first 20 Q without the clock Q is the expermental. Everyone has clock??</p>
<p>the Chair Q
There are 12 chairs in each row and 6 chairs in each coloms
if remove 1 row and 2 colomns, how many chair??</p>
<p>0 is absolutely integer, the answer must be 9970 b/c I do it lol</p>
<p>What did you guys do on the remove chair question?
I think it was 12<em>6-10</em>5=22.</p>
<p>I still don’t understand now. Why 10*5</p>
<p>what might possibly be the curve?</p>
<p>You can think it in this way.
12 in one row, 6 in one col, so:
First you remove 1 row, and that leaves you (6-1)<em>12–>5</em>12
Then you remove 2 cols, and that leaves you 5<em>(12-2)–>5</em>10</p>