<p>they had this really weird question, and I hope something can confirm for me that it was experimental. I had 4 math sections, so I knew one of them had to be experimental</p>
<p>Question was like this:
x= (5^1304) * (2^1308)
How many digits does x have?</p>
<p>Choices were all in the 1000-2000 range.</p>
<p>I'm like, ***? How would you actually do this problem?</p>
<p>Every 2x5 is just going to add a zero to the end of the product. So it's just 2^4 with 1304 zeros on the end. So 1306 digits.</p>
<p>Thanks, I didn't realzie that earlier</p>
<p>It was experimental right because one of my friends didn't have it</p>
<p>dude did that section also have a problem with a system of equations like:</p>
<p>z=w+x-y
z=...
z=...</p>
<p>or something like that?</p>
<p>PS. I HOPE its experimental</p>
<p>it was experimental because my test did not have that question</p>
<p>I still don't get it.
I'm sure glad I didn't get the math experimental, or else I would've FREAKED the heck out o_o</p>
<p>thank god.! all my math sections were good, until i came to this hard one where i ommited 2 and guessed on 2! i was like freaking out. phew</p>
<p>You could also figure it out with logs.</p>
<p>log(5^1304 *2^1038) = log(5^1304 * 2^1304) + log(2^4) = 1304 + log(16) = 1305.2</p>
<p>You obviously can't have 1305.2 digits (each place represents a power of ten) so you have to round up to 1306 digits.</p>
<p>(This technique works with all numbers. Example: log(123456)=5.09-->6 digits)</p>
<p>every 5 times 2 equal 10, which is jsut an extra 0 digit</p>
<p>so you break up 2^1308 into 2^1304*2^4. </p>
<p>2^1304*5^1304 simply produce 1304 10's, which means 1304 digits</p>
<p>now times that by 2^4, which produces 16, two more additonal digits</p>
<p>Add em up for 1306</p>
<p>BTW, thanks a lot Hamster. He was the one who originally suggested it</p>
<p>FYI: I have two X chromosomes.</p>
<p>hamster, i like that way of pointing out you are a female</p>
<p>my friend got a problem like this</p>
<p>if *k is to represent a set of consecutive intergers starting at 10 what would the 4th from last digit in *80 be if *4 = 10,111,213
a 4
b 5
c 6
d 7
e 8</p>
<p>I have no clue how to do it, and i got an 800 in math my first time. I did NOT get this one today</p>
<p>everyone agree this is experimental?...i hope to god it is so i mjust makinnn sure</p>
<p>habdragon08 are you sure that's the question? That doesn't make any sense. (I also got an 800 and it's greek to me...)</p>
<p>I had 4 math sections also, but I didn't have that question...</p>
<p>Your friend's problem (at least one you quoted :) ) looks similar to this
<a href="http://talk.collegeconfidential.com/showthread.php?t=91853%5B/url%5D">http://talk.collegeconfidential.com/showthread.php?t=91853</a>
if you notice that *4 is a sequence 10 11 12 13.</p>
<p>wow that problem looks daunting. I didn't take that version of the test but I just wanted to know if 1307 was a choice for the x= (5^1304) * (2^1308) problem.</p>
<p>I believe the answer is 1306.</p>
<p>I am so confused, why would you break it up into 2^4??</p>
<p>has anyone solved the *k problem yet? I think it's d)7. Bc *4 means a number thats made of 4 consecutive integers starting with 10 -> 10 11 12 13. So *80 means 10 11 12 13 14 ... 85 86 87 88 89. 4th digit from last is 7. Someone verify me please? I'm glad I didn't have this q on the test...</p>