<p>lol good for you. how long did it take to convince her to believe you</p>
<p>
I think it was just II: (x+2)^2. X could be a small negative and y could be a large one.</p>
<p>@sAxsKy</p>
<p>are you taking about which one was the greatest with xyz</p>
<p>I think he means the one where II was the answer is it was like (y-2) 3/2 or something. :|</p>
<p>Joey: well it took about 473219372189372819 explanations of how i knew they did it. and how they managed to switch scantrons but i still don’t think she understood, even after i acted it out with another girl who saw it happen. and i went through like 5 pieces of evidence… including that both went to the bathroom after the test was done, the proctor remarking on the boy’s handwriting being too small in the beginning and then the girl’s being too small in the end, the fact that i watched her pick his scantron up next to mine… etc</p>
<p>It was a multiple choice question:</p>
<p>X^2 - Y^2</p>
<p>(X-Y)^2</p>
<p>?</p>
<p>Which of the choices MUST be positive.</p>
<p>I was stupid and put I and II when the answer was just II…I got 4 wrong on the entire MC with 3 omits and 2 wrong on the grid in. Is that like a 680?</p>
<p>Does anybody remember the question with the volume of the cube and sqrt(15) as the answer?</p>
<p>I am 100% positive the answer was 800, and I know this through many ways.
Most people probably used 45-45-90 rules, but it’s a general rule that squares that are inscribed in squares at each sides’ midpoint has an area that’s 1/2 of the larger squared. Thus, the smallest square was 200, the intermediate square was 400, and the largest square was 800.</p>
<p>I am also 100% certain that the questoin never involved having 10 as a side length, because i remember staring at the question for 5 minutes to make sure that I didn’t make a stupid mistake reading the question or solving the math. The wording was that the “smallest square has an area of 200”. Never did it mention any sidelengths.</p>
<p>So it’s quite possible that you’re confusing it with a different question. Either that or you’re just remembering wrong.</p>
<p>That’s gonna be around a 650, maybe lower.</p>
<p>That’s how I did it… thank you wanderyonder you ****ing savior. :P</p>
<p>i got the same…im guessing around 760</p>
<p>I feel so stupid. This was my first real SAT and was a spur of the moment registration so I still have May to make up for it.</p>
<p>i still disagree with the p r t one on the consolidated list written as 10r=p… </p>
<p>if you picked 100 as the starting number, and r is 20 percent of the first number, r would equal 20. then you have 100=50p, p would equal 2. (in decimal form), representing 200 percent. you keep that in decimal form as 2, and as your answer you get 10p=r ( 10(2)=20 )</p>
<p>saxsky i did the same… that was actually the only question i got wrong lol</p>
<p>hmmmm… i think wanderyonder’s right
now i remember that i calculated (10root2)^2 just in case to make sure that the smallest square had a side of 10root2 and used the 45-45-90 to get my answer</p>
<p>Is that an experimental problem?</p>
<p>@tom51293</p>
<p>the question was something like:
a cube has dimensions of 2, 3x, and x and a volume of 90. what is the value of x?</p>
<p>x = root 15</p>
<p>if i got 2x mc, and 1x grids, what would that be?</p>
<p>silenceizsik, its “p percent of whatever.” so if its 50 percent, p would be 50, not .50.</p>
<p>the question was like r is 20 percent of t and t is p percent of 50.
if r is 2, t is 10. if t is 10, p is 20.
then we can verify that 10r=p (10*2=20)</p>