<p>maybe this would help:</p>
<p>Oh Dear, Sweet, Merciful Jesus... I can't believe you people thought this was easy...there goes the curve. I had to leave about 5 blank; I work at a snail's pace though.</p>
<p>That's a nice picture. Is it Paint?</p>
<p>Tedjn,i believe all of the test centers have now administered the test because it is past 8 AM across the US and international testing is earlier than us...if its always given on saturday. i think we're okay to discuss detail. but im not sure!!</p>
<p>Other people are discussing other tests, which I have even participated in because I was not subject to whatever nondisclosure agreement they pile upon us. Mostly, it is a selfish desire to force a better curve that keeps me from discussing the test.</p>
<p>Far be it from me to stop you guys from talking though. I may even join in :)</p>
<p>haha, no i totally agree! But I'm curious by nature and i don't know if i can wait much longer!!! anyone want to start?</p>
<p>for 49, did anyone get in the 7s?</p>
<p>Yep, I got within the 7s.</p>
<p>@alohasam89,</p>
<p>20 minutes is mighty fast. I remember at the twenty minute mark I thought I was doing pretty well, but I was only on 32!</p>
<p>i live on the west coast, and were all done, so...talk away!</p>
<p>Love it! Thanks :) I'm actually a curious person too, hidden under all that slimy selfishness ;)</p>
<p>I guess I'll begin with a comment about #50. The key fact to recognize was that six consecutive multiples of three will have at least one multiple of nine. Adding the digits together, we find that for the monster number to be divisible by 9, A+B+C would need to be 5, 14, or 23. Only 5 was a choice, though.</p>
<p>Kay the trapezoid one everyone's talking about...
was the height something like 2.4375
so you got the area by (4+2.5)x2.4375/2
..
And the A+B+C.. i just multiplied 33,36,39,42,45,48
which produced 4203239040... and since it was 4ABC239040, A+B+C=2+0+3= 5!!</p>
<p>I think i messed this thing up.. im probably gonna cancel my score.... ugh</p>
<p>Oh what did you guys get for the f(x)=g(x) and how do you find the value of x? there were 3 choices:
I. you graph and find the x value
II. you graph and find the y value
III. You graph f(x)-g(x) and find the zeros</p>
<p>It was something liek that.. i did III only what did you guys do</p>
<p>I thought it was I and III</p>
<p>I and III??</p>
<p>Yes, I agree with you on the trapezoid question. For the question you posed, I actually chose both I and III.</p>
<p>I. Graphing both and finding the x-coordinate of their intersection means finding an x value in which the y values (f(x) and g(x)) are equal to each other, which is what our goal was.</p>
<p>III. Really an offshoot of I. When f(x) = g(x), h(x) = 0 and we are really still finding the x-coordinates where f(x) and g(x) are equal, just disguised under the term 'zero.'</p>
<p>tedjn..haha, i knew you were just dying to talk about it!!</p>
<p>Can't stop me now :P</p>
<p>Area of trap was 7.9</p>
<p>--
I and III</p>
<p>oh shoot u guys are right...
there goes one mark..</p>
<p>kay that n-2 is a prime number and n+2 is a prime number, then N must be a prime number question
was it 15?</p>
<p>and the log2(k2+somethingk)=6... did you get -16 as your answer?</p>
<p>ahh so many questions!</p>
<p>Interestingly enough, if on the trapezoid problem you found the area under the curve bounded by the 2.5 unit chord, the answer I got was somewhere around 8.06. Was that an answer choice?</p>
<p>haha. ok how about that graph that was given, f(x)= 1/ g(x)...I drew a total blank about whether or not that meant inverse!!! but then when i thought about i was like no..it doesn't but it was too late to figure it out. i think the question was about where g(x) would equal zero</p>
<p>yes those choices sound familiar babeexphat.</p>