Math Question!meeep

Test Preparation SAT Preparation
1

<ol>
<li>In triable abc above if a>b>c, which of the following must be true?
I.60<a<180
II.45<b<90
III. 0<c<60</li>
</ol>

<p>a. I only
b. II only
c. I and III only
d. II and III only
e. I, II, and III</p>

<p>Explanation please and tricks if you have any to solving questions like these.</p>

<ol>
<li>Paul has 24 large pieces of candy, and kate has 40 small pieces of candy. they have agreed to make trades of 1 of pauls large candies for 3 of kates small candies. after how many such trades will paul and kate each have an equal number of candies?</li>
</ol>

<p>Trick to solving those types of problems?!</p>

<ol>
<li>If x^10 = 5555 and x^9/y=5, what is the value of xy?</li>
</ol>

<p>what is the trick to solving problems like these?</p>

2

<p>(x^9)/y or x^(9/y) ?</p>

3

<p>I got I, III for first, 9 for second, and 1111 for third.</p>

4

<p>My bad, I think its 4 for the second one. Dang that was tricky.</p>

5

<p>8 for second, not 9</p>

6

<p>No, because they are TRADING the candy. Therefore the equation would be:</p>

<p>24-n+3n=40-3n+n</p>

7

<p>okay i don’t care what you guys got lolz i care about your explanations. and 34 is 4 and 38 is 1111 and 28 is C</p>

<p>Explanation please and tricks if you have any to solving questions like these.</p>

8

<p>No tricks, just plain math.</p>

<p>1- Just logic it out.
2. Set up equation:
24-n+3n=40-3n+n
3. x^10=5555
x^10 / x = 5555/x
x^9 = 5555/x</p>

<p>Plug it into the other equation.</p>

9

<p>can someone explain the logic to 28? and for 34, if you do the equation you did, you get n=16…</p>

10

<p>You did it wrong. Try again.</p>

11

<p>touche… lol yes i thought there was a negative sign before the 24 for w.e reason… thanks</p>

<p>can someone explain the logic to 28?</p>

12

<p>explain 28 plox!</p>

13

<p>For the second problem you dont need to use algebra. See, there is a 16 candy gap. Each trade results in the gap being reduced by 4. So you need 16/4 =4 trades.</p>

<p>Imo, its best practice to get a intuition for these kinds of things, instead of trying to chug stuff into algebra.</p>

14

<p>yah… someone explain 28!?</p>

15

<p>For 28…</p>

<p>If a is the biggest angle, it has to be more than 60 (but less than 180) b/c if it were 60 or less, then the three angles together could never add up to 180:</p>

<p>60 or less + less than 60 + less than 60 = less than 180.</p>

<p>Similiarly, the smallest one cannot be 60 or more, because since the other two are bigger:</p>

<p>60 or more + more than 60 + more than 60 = more than 180.</p>

16

<p>so 28 is C?</p>

17

<p>Yes, it is c.</p>

<p>And as for why II is wrong: b could be smaller than 45…for example:
a = 120, b= 31, c= 29</p>

18

<p>ahh thanks, so the best idea to solve something like this is to list the 3 conditions?</p>

19

<p>I don’t know what’s the best way. All I can tell you is that on SAT problems, I constantly try to make up numbers that fit the given situation. And when some problem says that something MUST be true, I try to find counterexamples. One counterexample proves something is false, and that is often easier than proving that what remains is true. So for each of the three conditions in this problem, in my mind I was attacking them, trying to show they were wrong. Often, when you do that, you get the insight that shows you why they are right!</p>

<p>Well – not sure that this helps to answer your question…</p>