<p>Im taking math 2c on saturday and ive been practicing from barrons and sparknotes. the tests i do on sparknotes i get around low-mid 700s, and on barrons i get low 600s. im really frustrated right now im really hoping to get an 800 if not at least a high 700. How does sparknotes and barrons compare with the real test?</p>
<p>Barrons is much, much harder. Sparknotes is realistic. CB is the most realistic.</p>
<p>^ i know barrons is harder...but *** a 620 thats a raw score of less than half T.T. i dont have the cb book for math but would the cb subject test book work (the one with 2 of each subject tests)</p>
<p>Lawl Barron's is crap; it's only useful in helping you practice working through math-related problems quickly. </p>
<p>Ummm I got abysmal scores in Barron's and a 720 on the real thing (the first time), which is still pretty... not-desirable... but I didn't really look at the instructional material or anything. Low 600s in Barron's could easy translate to high 700s if you feel that you know your stuff.</p>
<p>^ few things im still not totally clear on are sequences/series, binomial therom, and parametric equations (i'm sure i have more but these only thing i could think up of atm) anyone have good explanation for those? especially sequences and series because barrons and pr gives bad explanation for them</p>
<p>Sequence - #1, #2, #3.....
Series - #1 + #2 + #3......</p>
<p>These are either arithmetic (separated by a number arithmetically called the common difference) or geometric (separated by a number multiplicatively called the common ratio).</p>
<p>The nth term of an arithmetic sequence
Tn = T1 + (n-1)d d = common difference
The nth term of a geometric sequence
Tn = T1 * r^(n-1) r = common ratio
Sum of the first nth terms of an arithmetic
Sn = n(T1 + Tn)/2
Sum of the first nth terms of a geometric
Sn = T1(1 - R^n)/(1 - R)
Infinite sums of a geometric
If |r|>1, the series diverges
|r|<1, S = T1/(1 - r)</p>
<p>Binomial theorem isn't on math II.
For parametric equations, just rewrite y in terms of x by eliminating the parameter (use algebra and substitution). The only questions I've seen ask the slope or the y/x intercept. Piece of cake in y = mx + b form.</p>
<p>^ are you sure? because the binomial theorm was tested in the barrons book and also how would you do this: </p>
<p>The graph of xy - 4x - 2y - 4 = 0 can be expressed as a set of parametric equations. If y = 4t/(t-3) and x = f(t), then f(t) =</p>
<p>(A) t+1
(B) t-1
(C) 3t-3
(D) (t-3)/4t
(E) (t-3)/2</p>
<p>and:</p>
<p>In the geometric series gn, where g1 = 3 and g3 = , what is g10?
(A) 3/1024
(B) 3/512
(C) 3/16
(D) 3/8
(E) 3/2</p>
<p>Haha, I sympathize because I'm so freakin' frustrated with the Barron's and keep scoring around 500-600, but I took a Kaplan test and got 750. Even so, all I can think about is the Barron's and feeling like crap and hating my awful math teacher even more than I usually do.</p>
<p>Guys, HELP! I amtaking MAths on Saturday, but I met one term that I have never met before- least squares linear regression. what does it mean? is it frequently met?</p>
<p>least squares linear regression is simply the "line of best fit." You've probably used it in your classes before, finding a line that fits data best (probably using a linear regression). The reason they call it "least squares" regression line is because it minimizes the sum of the squares of the distance of the data points to the line. But I don't think you need to know that. So:</p>
<p>line of best fit = least squares regression line (this is the more used term .. least squares linear regression works too though I guess)</p>
<p>The graph of xy - 4x - 2y - 4 = 0 can be expressed as a set of parametric equations. If y = 4t/(t-3) and x = f(t), then f(t) =</p>
<p>(A) t+1
(B) t-1
(C) 3t-3
(D) (t-3)/4t
(E) (t-3)/2</p>
<p>It's B, just isolate x, then substitute for y, and you will get [(12t-12)/(t-3)]/[12/(t-3)]. Don't be fooled by the parametric stuff. It's just algebra in the end.</p>
<p>In the geometric series gn, where g1 = 3 and g3 = , what is g10?
(A) 3/1024
(B) 3/512
(C) 3/16
(D) 3/8
(E) 3/2</p>
<p>what's g3? If g3 is 3/4, then the answer is B. Just multiply g1 by 1/2 (i.e. g2 = g1 * 1/2, g3=g2*1/2, and so on) until you get to g10</p>
<p>Also, I did not see the Binomial Theorem on the SAT 2 math iic when I took it but least squares regression did pop up so make sure you can do it on your calculator.</p>