<p>Thanks a lot, silverturtle. </p>
<p>Looks like I am looking at a mid-700.</p>
<p>sorry which molecule is C?</p>
<p>I think C) was the alcohol. Correct me if I’m wrong on that.</p>
<p>did it have the double bond at the tip?</p>
<p>i remember arriving at c after crossing off every other choice that has an isomer.</p>
<p>i think it might have been an organi acid.</p>
<p>sorry just to clarify A was a symmetric molecule?</p>
<p>i’m pretty sure the isomer one was a. the double bond one is definitely not it if it had more than 3 carbons.</p>
<p>that is what i thought</p>
<p>was the question asking which is an isomer or which cannot have an isomer?</p>
<p>anyone remember the question on the kinetic molecular theory?</p>
<p>I read the question as what CANNOT have an isomer.</p>
<p>
</p>
<p>Which of the following can the Kinetic Molecular Theory not describe? </p>
<p>(A) Something dependence on something (temperature or pressure or volume)
(B) Something dependence on something (temperature or pressure or volume)
(C) Something dependence on something (temperature or pressure or volume)
(D) Diffusion of gases
(E) Heats of formation</p>
<p>I put (E).</p>
<p>ok that is what i thought,
therefore it is A because A is the only one with a parallel structure and that means no matter how one turns it it will be the same.</p>
<p>^ what if cl is next to cl ? or one cl is opposite another?</p>
<p>im pretty sure the isomer one was B because it had 2 carbons.</p>
<p>^ 2 carbons and what?</p>
<p>@silverturtle</p>
<p>Yes, the answer was most definitely E.</p>
<p>^ now was it 2 carbons double boned C2? Or did it have two carbons bonded with some other junk? if it was the latter, it most likely posessed an isomer. Btw to whoever said they put an organic acid for the isomer question, im almost positive that’s incorrect. sorry :(</p>
<p>and Cl? we did one just like it in my AP class and I was torn between A and B and decided it was definitely B.</p>
<p>@silverturtle
are you sure heat of formation was choice E?</p>
<p>
</p>
<p>Positive. I can still see that part of the question in my mind.</p>