November 2009 SAT Math (US only)

<p>@checkmate do you remember the choices for that xy=x thing?</p>

<p>wait…did international students and US students get different tests???</p>

<p>and I also realized that this test was the same as the one I wrote in March (which was only offered in the US,I live in Canada,so I wrote it in Buffalo,NY)…</p>

<p>But yeah…it’s odd…</p>

<p>yeah.
I. when x is 1 why is always zero
II. x is always zero when y is 1
III. this one was obvious but cant remember</p>

<p>i remember</p>

<p>x cannot equal y
if x=0 y cant equal one?
if y=0 x cant equal one?</p>

<p>im not sure but i put II only. i cound a contradiction with III</p>

<p>wait…did international students and US students get different tests???</p>

<p>and I also realized that this test was the same as the one I wrote in March (which was only offered in the US,I live in Canada,so I wrote it in Buffalo,NY)…</p>

<p>But yeah…it’s odd…</p>

<p>@checkmate
yea i got 2 grid ins
so one of them is experimental
i hope they count the first one because that one seemed easier</p>

<p>Couldn’t I be true if both X and Y are zero?</p>

<p>maybe i did but I and II only. all i remember is that is was question number 14, and it was C.</p>

<p>Oh, yea. I remember a problem about folding a piece of paper in half 3-4 times and punching a hole in it. I’ve never seen that type of problem before on the Math SAT. It was still easy, but I found it funny because it reminded me of the cog. test in 8th grade.</p>

<p>wait…did international students and US students get different tests???</p>

<p>and I also realized that this test was the same as the one I wrote in March (which was only offered in the US,I live in Canada,so I wrote it in Buffalo,NY)…</p>

<p>But yeah…it’s odd… …</p>

<p>187 yeah I remember that one. I think the answer was D for it.</p>

<p>yea international is differ.
@checkmate
i think we got the same booklet</p>

<p>x cannot equal y
if x=0 y cant equal one?
if y=0 x cant equal one?</p>

<p>Reasoning from that it had to be I and II only since III doesn’t make much sense. If X was 1 then it couldn’t equal X when multiplied by Y</p>

<p>ycm I don’t remember a question like that…</p>

<p>cacciato, x and y could both be zero but at the same time y could be any interger and you wouldnt know it</p>

<p>In reference to the sock question, to ensure that you receive one pair shouldn’t it be 7? I see 4 as the consensus. It did not say that you choose a different sock each time, right? To ensure that one receives a pair, you need to choose 7, since the same sock could be drawn 6 times in a row.</p>

<p>mifune tell me when you get to this forum so we can discuss the answers because I’m pretty sure we got the same booklet.</p>

<p>anyone remember a question with M being a constant and you had to find it?</p>

<p>mifune - that’s what I got!! But then again…I’m not sure…but yeahh I think you’re right WOOT! :)</p>

<p>the answer was I and II only. The first two were correct, the third wasn’t because x and y could have both equaled 0 or 1</p>