<p>abc, the events are independent of each other. which i thought meant u multiply their probabilities</p>
<p>There are two possible ways to get one phone call of each type:either the local call first followed by the long distance call, or the other way around.</p>
<p>It’s 2/9. You’re overthinking bro</p>
<p>yea but theyre two independent events so it shouldnt matter? i think you over thought it</p>
<p>@golfer
It was a bit more depth than that. It wasn’t what was the chance of getting both, but I don’t remember what it was, I do remember 4/9 though.</p>
<p>The chances of first getting a local call, and then getting a long distance call is (2/3)(1/3) = 2/9. The chances of first getting a long distance call and then getting a local call is (1/3)(2/3) = 2/9. 2/9+2/9 = 4/9. I do not believe that this is over thinking the question, especially considering that it was one of the later questions.</p>
<p>I agree with abc.</p>
<p>Yeah, it’s 4/9. Pretty sure about my answer. 1-((1/3)^2+(2/3)^2)=4/9. The prob is equal 1 minus the prob of getting 2 local calls ((1/3)^2) minus the prob getting 2 international calls ((2/3)^2)</p>
<p>hmmm but didn’t the question say what is the probability of getting a local in town a and then a long in town b, meaning they were two independent events? so it would simply be 2/3 for the first times 1/3 for the second = 2/9</p>
<p>^you guys are making me nervous…
who’s right?</p>
<p>im not sure now im starting to doubt myself haha it all depends on how it was worded</p>
<p>I agree with goldnano. His/ Her explanation is the best. If both of the event is the same, for eg, local and local, then arrangement doesnt matter. So, to be safe, you should use 1 minus to total of local, local and internationl,international. That way, you are safe. I did that and did other method and got the same answer. 4/9</p>
<p>Be reasonable, it was near the end, I doubt they’d put in a giveaway probability question, and there’s no doubt in my mind that there was some spin to it.</p>
<p>^that’s what I was thinking chanto… i was like, hmm it seems easy and 2/9 is A…oh well…</p>
<p>It’s just one wrong, don’t stress.</p>
<p>^oh crap. haha well there goes my dream of 750+…
does anyone how many i can
- get wrong
- omit</p>
<p>to get 750+? just an estimate would be fine
thanks</p>
<p>yea thats true you’re probably right^</p>
<p>^lol i wish it was just one. that makes at least 3 i think…</p>
<p>rainbow…i think you need a net score of like 43 for an 800. so 750 would likely be 38. Right?</p>
<p>yea that sounds about right golfer</p>
<p>also nobody really answered my question before everybody just kinda passed over it but there are some new people now…</p>
<p>for the one where it was like between the interval [-4,4] did it say that the pairs (m,n) had to be consecutive or something along those lines?</p>